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GuDViN
3 months ago
11

Which are the roots of the quadratic function f(b) = b2 – 75? Select two options. b = 5 StartRoot 3 EndRoot b = Negative 5 Start

Root 5 Endroot b = 3 StartRoot 5 Endroot b = Negative 3 StartRoot 5 EndRoot b = 25 StartRoot 5 EndRoot

Mathematics
2 answers:
zzz [12.3K]3 months ago
8 0

Answer:

b = 5√3

b = -5√3

Step-by-step explanation:

We have

f(b)=b^{2}-75

Keep in mind, the root of a function corresponds to the value of x at which the function's output is zero.

In this case

The roots of the equation are the b values for which f(b) equals zero.

Thus

For f(b)=0

b^{2}-75=0

b^{2}=75

Take the square root of both sides

b=(+/-)\sqrt{75}

Now simplify

b=(+/-)5\sqrt{3}

b=5\sqrt{3}  and b=-5\sqrt{3}

So we find that

b = 5√3

b = -5√3

Leona [12.6K]3 months ago
6 0

The roots of the quadratic equation are 5√3 and -5√3

Further explanation

To find the Discriminant for a quadratic formula, ( ax² + bx + c = 0 ), use this:

D = b² - 4ac

Based on the Discriminant's value, we can infer the number of solutions the equation may have following these criteria:

D < 0 → No Real Roots

D = 0 → One Real Root

D > 0 → Two Real Roots

An axis of symmetry in the quadratic equation y = ax² + bx + c is:

\large {\boxed {x = \frac{-b}{2a} } }

Now let’s solve the problem!

Given:

f(b) = b^2 - 75

The roots of the function can be determined when f(b) = 0:

0 = b^2 - 75

b^2 = 75

b = \pm \sqrt{75}

b = \pm \sqrt{25 \times 3}

b = \pm \sqrt{25} \times \sqrt{3}

b = \pm 5 \times \sqrt{3}

b = \pm 5\sqrt{3}

b = 5\sqrt{3} \texttt{ or } b = -5\sqrt{3}

\texttt{ }

Learn more

  • Solving Quadratic Equations by Factoring:
  • Determine the Discriminant:
  • Formula of Quadratic Equations:

Answer details

Grade: High School

Subject: Mathematics

Chapter: Quadratic Equations

Keywords: Quadratic, Equation, Discriminant, Real, Number

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zzz [12365]

Answer:

The wheel's diameter in millimeters is 660.4

Step-by-step explanation:

The diameter of the wheel is 26 inches

as given

1 inch equals 25.4 millimeters

Multiplying both sides by 26

26 inches = 26*25.4 millimeters

=>26 inches = 660.4 mm.

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3 0
3 months ago
The sequence 6, 18, 54, 162, … shows the number of pushups Kendall did each week, starting
Svet_ta [12734]

a) The sequence is geometric.

b) The subsequent term is 486

c) The rule is: a_n=6(3)^{n-1}

The 20th term will be: a_{20}=6973568802

Step-by-step explanation:

The series 6, 18, 54, 162, ... depicts the number of push-ups Kendall performed each week, starting from her initial week of exercise.

Part a) Is this sequence arithmetic or geometric?

An arithmetic sequence has a constant difference between consecutive terms.

In the given series 6, 18, 54, 162,

18-6 = 12

54-18= 36

The differences are not constant, thus it isn’t arithmetic.

A geometric sequence maintains a constant ratio between consecutive terms.

In this series 6, 18, 54, 162,

18/6 = 3

54/18 = 3

162/54 = 3

The ratios remain constant; therefore, the sequence is geometric.

The sequence in question is geometric.

Part b) How can you determine the next number in the series?

The next number can be calculated using the following formula:

a_n=a(r)^{n-1}

where a_n= nth term

a= first term

r= common ratio

The next number represents the 5th term of the sequence.

To find the 5th term:

a_n=a(r)^{n-1}\\a_5=6(3)^{5-1}\\a_5=6(3)^4\\a_5=6*81\\a_5=486

Thus, the next term in the sequence is 486

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The rule for determining the 20th week is:

a_n=6(3)^{n-1}

Here n=20

Calculating the 20th week

a_n=6(3)^{n-1}\\a_{20}=6(3)^{20-1}\\a_(20)=6(3)^{19}\\a_{20}=6973568802

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