A 40-degree angle may be applicable for this question
Answer:
55°
Step-by-step explanation:
The problem does not have a suitable diagram. Please check the attachment for the diagram.
Observing the diagram, it is evident that the triangle is isosceles, as it has two sides that are congruent (i.e., the same length). Since these sides are identical, the base angles are consequently also equal.
From the diagram, <EFG = <EGF
Since <EFG = 55°, it follows that <EGF = y = 55°
Thus, the value of y is established as 55°
There are 2 beginner, 6 intermediate, and 3 advanced books, totaling 11.
P(advanced) = 3/11
replaced
P(beginner) = 2/11
P(both) = 3/11 * 2/11 = 6/121 <=
A.) P(t) = P0e^(kt)
P(20/60) = 40 e^(20k/60)
80 = 40 e^(k/3)
e^(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)
b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells
d.) Rate of change = e^(8k) = e^(8(3ln(2))) = e^(24ln(2)) = e^(16.6355) = 16777216 cells/hour
e.) P(t) = 40(2)^(3t); t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
t = ln(25,000)/ln(8) = 4.87 hours
Answer:
y = 2.09x^2 + 0.33x + 3.06
Detailed explanation: