The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi
1 answer:
Answer:
a
P(X \le 250 ) = 0.7564 [/tex], ,
b
c
Step-by-step explanation:
As per the question, we know that
The value for
The value for
In general, the Weibull distribution function is expressed mathematically as
Typically, the probability for a specimen's lifetime being no more than 250 is mathematically illustrated as
Usually, the probability that a specimen's lifespan is below 250
[texP(X < 250 ) =1 - e^{- (\frac{250}{220} )^{2.7}}[/tex]
Usually, the probability that a specimen's life is more than 300
[texP(X < 300) =1- [1 - e^{- (\frac{300}{220} )^{2.7}}][/tex]
Generally, the likelihood that a specimen's lifespan falls between 100 and 250 is
=>
=>
=>
=>
Generally, this value is such that precisely 50% of all specimens
=>
=>
=>
=>
=>
=>
You might be interested in
Answer:
The variable x lies within the interval of all positive real numbers less than 5 cm.
Detailed solution:
Problem statement:
Determine the volume of the open-topped box as a function of the side length x (in centimeters) of the square cutouts.
Refer to the provided diagram for clarity.
Define:
x → length in centimeters of each square cutout side
The volume of the box with open top can be written as:
Given this, we have:
By substitution:
Determine the domain of x:
Because:
Therefore:
Domain is the interval (0,5)
That means all real numbers strictly greater than zero and less than 5 cm are valid for x.
Hence, the volume V as a function of x is:
Answer:
Hello! Your question appears to be missing details; here is the complete version
Ix = 0 Ux =
Iz = 0 Uz =
Iy = 5 Uy = 10
Step-by-step explanation:
Ix = 0 Ux =
Iz = 0 Uz =
Iy = 5 Uy = 10
This provides a comprehensive solution below
