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Reil
7 days ago
15

give an example on an addition problem in which you would and would not group the addends differently to add

Mathematics
1 answer:
AnnZ [9K]7 days ago
3 0
Addends refer to the numbers being summed in an equation. 

Their arrangement only matters if parentheses are utilized to modify the usual Order of Operations. 

For example:
2 - (8 + 3)  in this case, 8 and 3 must be grouped first before tackling the subtraction.

Any addition scenario without parentheses can similarly function where the grouping is irrelevant.
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Answer:

The total expected value and standard deviation of your winnings are -$0.081 and $3, respectively.

Step-by-step explanation:

In European roulette, a wheel with 37 slots is spun: 18 are red, 18 are black, and 1 is green.

Bettors can wager on either red or black. Winning on their chosen color means they double their bet, while losing means they forfeit their stake.

Define the probability for the ball landing in a red slot = \frac{18}{37}

The probability of it landing in a black slot = \frac{18}{37}

The probability for landing in the green slot = \frac{1}{37}

Since bets are only placed on red or black,

The winning probability = \frac{18}{37}

and losing probability = \frac{18}{37}+\frac{1}{37}

= \frac{19}{37}

If a gambler wins, they receive $3, and if they lose, it amounts to -$3.

The expected value of the total winnings is hence;

E(X) = \sum X \times P(X)

= \$3 \times \frac{18}{37} + (-\$3 \times \frac{19}{37})

= \$3 \times (-\frac{1}{37})  = -$0.081

Furthermore, the standard deviation of the total winnings is given by;

S.D.(X) = \sqrt{(\sum X^{2} \times P(X))-(\sum X \times P(X))^{2} }

<pTherefore, E(X^{2})=\sum X^{2} \times P(X)

= \$3^{2} \times \frac{18}{37} + (-\$3^{2} \times \frac{19}{37})

= \$9 \times (\frac{18}{37}+\frac{19}{37})  = $9

Thus, S.D.(X) = \sqrt{\$9-(-\$0.081)^{2} }

= \sqrt{8.993}  = $2.99 ≈ $3

Consequently, the anticipated value and standard deviation of your total winnings are -$0.081 and $3, respectively.

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