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DerKrebs
1 month ago
7

what is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?

Mathematics
3 answers:
lawyer [12.5K]1 month ago
6 0

Response:

8\frac{1}{8}

Detailed explanation:

The triangle's sides are 2 \frac{1}{8} \:\text{feet}, 3 \frac{1}{2} \:\text{feet}, and 2 \frac{1}{2} \:\text{feet}.

To calculate the distance around the triangle, we must sum all three sides.

This gives the total distance around the triangle as 2 \frac{1}{8}+3 \frac{1}{2}+2 \frac{1}{2}

=2+3+2+\frac{1}{8} +\frac{1}{2} +\frac{1}{2}

=7+1+\frac{1}{8}

=8+\frac{1}{8}

=8\frac{1}{8} feet.

Thus, the perimeter of a triangle with sides measuring 2 \frac{1}{8} \:\text{feet}, 3 \frac{1}{2} \:\text{feet}, and 2 \frac{1}{2} \:\text{feet} equals 8\frac{1}{8} feet.

Zina [12.3K]1 month ago
5 0
The total distance around the triangle is 7 and 1/8. To find this, you should add the sides together, ensuring you use a common denominator of eight.
tester [12.3K]1 month ago
0 0

The result is 8 1/8

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