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3 days ago

what is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?

Mathematics

3 answers:

lawyer [3.9K]3 days ago

6 0

Response:

$8\frac{1}{8}$

Detailed explanation:

The triangle's sides are $2 \frac{1}{8} \:\text{feet}$ , $3 \frac{1}{2} \:\text{feet}$ , and $2 \frac{1}{2} \:\text{feet}$ .

To calculate the distance around the triangle, we must sum all three sides.

This gives the total distance around the triangle as $2 \frac{1}{8}+3 \frac{1}{2}+2 \frac{1}{2}$

$=2+3+2+\frac{1}{8} +\frac{1}{2} +\frac{1}{2}$

$=7+1+\frac{1}{8}$

$=8+\frac{1}{8}$

$=8\frac{1}{8}$ feet.

Thus, the perimeter of a triangle with sides measuring $2 \frac{1}{8} \:\text{feet}$ , $3 \frac{1}{2} \:\text{feet}$ , and $2 \frac{1}{2} \:\text{feet}$ equals $8\frac{1}{8}$ feet.

Zina [3.8K]3 days ago

5 0

The total distance around the triangle is 7 and 1/8. To find this, you should add the sides together, ensuring you use a common denominator of eight.

tester [3.8K]3 days ago

0 0

The result is 8 1/8

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