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babymother
14 days ago
11

One gallon is approximately 3.875 liters. Mario buys 1.5 gallons of gasoline for his lawn trimmer how many liters of gasoline, t

o the nearest tenth did Mario buy
Mathematics
2 answers:
tester [8.8K]14 days ago
7 0

Answer:

5.7

Step-by-step explanation:

No further explanation, just trust me on this

Zina [9.1K]14 days ago
7 0

Answer:

Ф∵∴∵Hello amazing person∵∴∵Ф

Your response should be:

5.8

Since 3.875 rounded to the tenth is 3.9, multiplying by 1.5 results in 5.8.

Step-by-step explanation:

I would appreciate being recognized as the brainliest!

Thank you for your time!

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Which transformations can be used to carry ABCD onto itself? The point of rotation is (3, 2). Check all that apply.
Leona [9271]

Both A and B.

This is due to the fact that X=3 cleanly divides the rectangle into two equal halves, causing any reflection to resemble the original shape.

Additionally, any shape with two lines of symmetry, when rotated 180 degrees, will align with one of the axes of symmetry and appear the same as the original shape.

7 0
29 days ago
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Find the measure of x. Line PU has points R and S between points P and U, lines QR and ST are parallel, line QR intersects line
Leona [9271]

Response:

  • Solution for x is 1

Detailed explanation:

Line PU acts as a transversal intersecting parallel lines QR and ST

The angles PRQ and UST sum to 180 degrees

  • 15(x+2) = 180 - 135
  • 15x + 30 = 45
  • 15x = 15
  • x = 1
5 0
14 days ago
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Suppose that there are 15 antennas in a store, of which 3 are defective. Assume all the defectives and all the functional antenn
PIT_PIT [9117]

Answer:

Step-by-step explanation:

There are 15 antennas in total.

Out of these, 3 are defective.

This means that 12 antennas are functioning: 15-3=12.

To ensure that no two defective antennas are adjacent, we need to have only one defective at a time placed between the functional ones.

So,

We align the 13 functional antennas, then look for the spaces where the defective antennas can fit

__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __

Each gap represented by an underscore indicates a possible location for a defective antenna, allowing for just one per space.

Consequently, there are 14 potential spots for the defective antennas. With 3 defectives, we are dealing with a combinatorial arrangement.

ⁿCr= n!/(n-r)!r!

The total number of arrangements possible is

14C3=14!/(14-3)!3!

14C3=14×13×12×11!/11!×3×2

14C3=14×13×12/6

That gives us 364 distinct ways to arrange them.

7 0
20 days ago
You are in an airplane 5.7 miles above the ground. What is the measure of BD⌢
AnnZ [9099]

Result:

6.1°; 425.86 m.

Step-by-step breakdown:

The information provided states that the airplane is at an altitude of 5.7 miles above ground level, while the "radius of Earth is about 4000 miles." Thus,

θ = 2 × cos^-1 (a/ (a + b)), where a = 4000 miles, and b = 5.7 miles.

θ = 2 × cos^-1 (4000/ (4000 + 5.7)) = 6.1°.

To calculate the distance in meters:

Change in distance = 6.1° /360° × 2π × 4000 miles = 425.86 meters.

Consequently, BD⌢ measures at 6.1° and the distance corresponding to this section of Earth is 425.86 meters.

6 0
22 days ago
Carmen is going to roll an 8-sided die 200 times. She predicts that she will roll a multiple of 4 twenty-five times. Based on th
AnnZ [9099]

Answer:

Carmen's estimate is too low, since rolling 200 times \frac{1}{4} results in a total of 50.

Step-by-step explanation:

Initially, we will define the sample space for this scenario.

The sample space is Ω = {1,2,3,4,5,6,7,8}

For the event A: "Rolling an 8-sided die to get a multiple of 4"

The probability for event A is P(A)=\frac{2}{8}=\frac{1}{4}

This is because there are two multiples of 4 (4 and 8) out of a total of eight numbers (1 through 8).

Next, considering the random variable X: "Total count of multiples of 4 if she rolls an 8-sided die 200 times"

X can be described as following a Binomial distribution.

X ~ Bi (n,p)

X ~ Bi (200,\frac{1}{4})

Where n is the number of rolls and p is the probability of success, defined as rolling a multiple of 4.

The mean for this variable is

E(X)=np=200.\frac{1}{4}=50

Thus, we conclude that Carmen's prediction is low, as rolling 200 times \frac{1}{4} yields 50.

4 0
19 days ago
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