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kow
3 months ago
8

For model 5, the tip of the blade travels 0.18 mile per revolution. What is the approximate speed, in revolutions per minute,for

model 5?

Mathematics
2 answers:
tester [12.3K]3 months ago
6 0

I also require the answer!


PIT_PIT [12.4K]3 months ago
3 0

Answer:

The approximate speed will be 19 revolutions per minute.

Step-by-step explanation:

In model 5, the length of the blade is 148 feet.

The maximum velocity of the blade tip reaches 200 miles per hour.

Per revolution, the blade tip covers 0.18 mile.

Revolutions per hour can be calculated as \frac{200}{0.18} = 1,111.

To find the speed per minute, divide by 1 minute (60 seconds).

\frac{1,111}{60} = 18.51 ≈ 19 revolutions per minute.

You might be interested in
Jerry is a judge he hears 5 cases every 2 3/8 per hours Jerry hears case at a constant rate How many cases does he hear per hour
tester [12383]
Approximately 2, I believe... I calculated it to be around 2.10. 
5 0
3 months ago
Read 2 more answers
Upgrading a certain software package requires installation of 68 new files. Files are installed consecutively. The installation
lawyer [12517]

Answer:

The chance of completing the entire package installation in under 12 minutes is 0.1271.

Step-by-step explanation:

We define X as a normal distribution representing the time taken in seconds to install the software. According to the Central Limit Theorem, X is approximately normal, where the mean is 15 and variance is 15, giving a standard deviation of √15 = 3.873.

To find the probability of the total installation lasting less than 12 minutes, which equals 720 seconds, each installation should average under 720/68 = 10.5882 seconds. Thus, we seek the probability that X is less than 10.5882. To do this, we will apply W, the standard deviation value of X, calculated via the formula provided.

Utilizing \phi, we reference the cumulative distribution function of the standard normal variable W, with values found in the attached file.

P(X < 10.5882) = P(\frac{X-15}{3.873} < \frac{10.5882-15}{3.873}) = P(W < -1,14)

Given the symmetry of the standard normal distribution density function, we ascertain \phi(-1.14) = 1-\phi(1.14) = 1-0.8729 = 0.1271.

Consequently, the probability that the installation process for the entire package is completed within 12 minutes is 0.1271.

Download pdf
7 0
2 months ago
Venetta buys 2 pounds of pistachios and 3 pounds of almonds. The pistachios cost $4 more per pound than the almonds. She pays a
babunello [11817]

Answer:

A. Combining one pound of pistachios with one pound of almonds costs $20.

C. Decreasing the almond quantity by one pound leads to a total price of $40.

E. The price p (in dollars) per pound of pistachios is represented by the equation 2p + 3(p – 4) = 48.

Step-by-step explanation:

Let:

x = cost per pound of pistachios

y = cost per pound of almonds

We know that

x = y + 4 (Equation A)

2x + 3y = 48 (Equation B)

Substitute x from Equation A into Equation B:

2(y + 4) + 3y = 48

2y + 8 + 3y = 48

5y = 48 – 8

y = 8

Find x:

x = 8 + 4 = 12

Therefore, pistachios cost $12 per pound and almonds cost $8 per pound.

Verify the statements:

Case A) One pound of each equals $20.

True, since 12 + 8 = 20.

Case B) Pistachios cost twice as much as almonds.

False, because 2 × 8 = $16 ≠ $12.

Case C) Reducing almond pounds by 1 yields $40 total.

True, as 2(12) + 2(8) = 24 +16 = 40.

Case D) The almond cost modeled by 2(a – 4) + 3a = 48.

False; it should be 2(a + 4) + 3a = 48.

Case E) The pistachio cost modeled by 2p + 3(p – 4) = 48.

True, since p = a + 4 implies a = p – 4.

8 0
3 months ago
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