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ANTONII
1 month ago
7

A steel pipe 100 cm long has an outside diameter of 2 cm and an inside diameter of 1.8 cm. If thee density of the steel is 7.8 g

rams per cm^3, what is the mass of the pipe to the nearest gram?
Mathematics
1 answer:
tester [12.3K]1 month ago
8 0

Answer:

The weight of the pipe is 465\ g

Step-by-step explanation:

step 1

Calculate the volume of the steel pipe

The volume can be determined by taking the area of the outer circle and subtracting the area of the inner circle, then multiplying by the length of the pipe

thus

V=\pi [r2^{2}-r1^{2}]L

we calculate

r2=2/2=1\ cm ---> the radius is obtained by halving the diameter

r1=1.8/2=0.9\ cm ---> the radius is calculated by dividing the diameter by two

L=100\ cm

\pi=3.14

replace values

V=(3.14)[1^{2}-0.9^{2}](100)=59.66\ cm^{3}

step 2

Determine the mass

The mass is found by multiplying density and volume

thus

m=7.8(59.66)=465\ g

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