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djverab
1 month ago
9

g A modal class in a histogram is the class that includes a. the largest number of observations. b. the smallest observation in

the data set. c. the largest observation in the data set. d. the smallest number of observations.
Mathematics
1 answer:
Leona [12.6K]1 month ago
4 0

Answer:

a. the class with the highest number of observations.

Step-by-step explanation:

The mode refers to the value within a dataset that appears most frequently. This indicates that it occurs with greater frequency than other values.

In a histogram, the modal class denotes the category that has the most observations, demonstrating that the variables in that category have a higher occurrence than those in others. Consequently, the answer sought is option a.

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Mike's Bikes has mountain bikes that usually sell for $275 on sale for $220. Mike used this ratio to find the percent change. Is
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No, Mike presented the ratio based on the change compared to the new amount. He ought to have utilized the ratio of the change against the original amount, which is represented as 55/275, or 20%.

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The lengths of the sides of triangle PQR are consecutive even integers. The perimeter of triangle PQR is 42 cm. What is the leng
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2 months ago
The amount of time it takes for a student to complete a statistics quiz is uniformly distributed (or, given by a random variable
Zina [12379]

Answer:

(A) 0.15625

(B) 0.1875

(C) Cannot be determined

Step-by-step explanation:

The time it takes for a student to finish a statistics quiz is uniformly distributed between 32 and 64 minutes.

Let's denote X as the duration needed for the student to complete the statistics quiz

Thus, X ~ U(32, 64)

The probability density function (PDF) for a uniform distribution is expressed as;

f(X) = \frac{1}{b-a},  a < X < b      where a = 32 and b = 64

The cumulative distribution function (CDF) is given by P(X <= x) = \frac{x-a}{b-a}

(A) The probability of a student taking longer than 59 minutes to complete the quiz = P(X > 59)

   P(X > 59) = 1 - P(X <= 59) = 1 - \frac{x-a}{b-a} = 1 - \frac{59-32}{64-32} = 1-\frac{27}{32} = 0.15625

(B) The probability that a student completes the quiz between 37 and 43 minutes = P(37 <= X <= 43)  = P(X <= 43) - P(X < 37)

    P(X <= 43) = \frac{43-32}{64-32} = \frac{11}{32} = 0.34375

    P(X < 37) = \frac{37-32}{64-32} = \frac{5}{32} = 0.15625

    P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875

(C) The probability that a student takes exactly 44.74 minutes to complete the quiz

     = P(X = 44.74)

This probability cannot be calculated as it is a continuous distribution, which doesn't provide probabilities for specific points.

3 0
2 months ago
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