Response:
MAD value comes out to be 3.
Detailed Breakdown:
The given sales forecasts for the last four months are 5, 6, 11, and 12 units.
To calculate the Mean Absolute Deviation (MAD) for these forecasts:
The average of the forecasts across four months is
.
Thus, the total of absolute differences between the forecast values and the average is = |5 - 8.5| + |6 - 8.5| + |11 - 8.5| + |12 - 8.5| = 3.5 + 2.5 + 2.5 + 3.5 = 12.
Hence, the MAD value will be =
(Final Answer)
The total number of individuals surveyed is 280. From the survey results, 65% were satisfied with the park's condition. Given that this satisfied group represents 182 people, we can calculate the overall survey population using this information.
The response is A
I hope this information is useful.
Answer:
The chance of completing the entire package installation in under 12 minutes is 0.1271.
Step-by-step explanation:
We define X as a normal distribution representing the time taken in seconds to install the software. According to the Central Limit Theorem, X is approximately normal, where the mean is 15 and variance is 15, giving a standard deviation of √15 = 3.873.
To find the probability of the total installation lasting less than 12 minutes, which equals 720 seconds, each installation should average under 720/68 = 10.5882 seconds. Thus, we seek the probability that X is less than 10.5882. To do this, we will apply W, the standard deviation value of X, calculated via the formula provided.
Utilizing
, we reference the cumulative distribution function of the standard normal variable W, with values found in the attached file.

Given the symmetry of the standard normal distribution density function, we ascertain
.
Consequently, the probability that the installation process for the entire package is completed within 12 minutes is 0.1271.
Solution
The number of weeks in a year is 52 weeks
In a typical year, where each flea treatment lasts 4 weeks, Jim's dog would receive

Conversely, during especially bad flea years, when treatments only last for 3 weeks, Jim's dog would need
So in a year, Jim's dog would need 17- 13 =4 extra treatments.
4 treatments at 3 weeks each total 4×3 =12 weeks of additional treatment