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gavmur
8 days ago
6

A random sample of 95 vehicles is taken from a large parking lot at an office park. Below is the type of each vehicle, and wheth

er it is owned or leased by the driver. A chi-square test will be conducted to determine if there is an association between type of vehicle and method of obtaining the vehicle. Which of the following expressions represents the expected count of leased SUVs? Car 29 21 Owned Leased SUV 20 10 1 Truck 1 4 O (A) 10 (B) (C) (35)(30) (D) (10-1.1.1) 111 (E) (11.1-10)
Mathematics
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Which expression is equivalent to StartFraction 3 x Superscript negative 6 Baseline y Superscript negative 3 Baseline Over 15 x
zzz [12365]

Answer:

The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction

Step-by-step explanation:

In order to simplify the expression \frac{3x^{-6}y^{-3} }{15x^{2}y^{10} } where x ≠ 0, y ≠ 0, we must work through the given expression.

\frac{3x^{-6}y^{-3} }{15x^{2}y^{10} }\\= \frac{3}{15} x^{-6-2}y^{-3-10}\\ = \frac{3}{15}x^{-8}y^{-13} \\ =\frac{1}{5}x^{-8}y^{-13} \\

The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction

6 0
2 months ago
Question 1(Multiple Choice Worth 2 points)
babunello [11817]
Here are 3 questions with their respective answers.

1) Find


\lim_{x \to \ 2^+} f(x)

Answer: 4.

Explanation:

This expression indicates the limit as the function f(x) approaches 2 from the right side.

You should apply the function (the line) from the right side of 2 and get as close to x = 2 as you can.

That line has an open circle at y = 4, which is the limit we are looking for.

2) Analyze the graph to see if the limit exists.

Answer:

\lim_{x \to \ 2^-} f(x) = 3

\lim_{x \to \ 2^+} f(x)=-3

To find each limit, utilize the function approaching from the direction of x.

It's important to note that since the two limits differ, it is concluded that the limit of the function as x approaches 2 does not exist.

3)
Answer: -1


\lim_{x \to \ 3^-} f(x) = -1

To determine the limit as the function approaches 3 from the left, follow the line ending with an open circle at (3, -1).

Hence, the limit is -1.
5 0
2 months ago
Read 2 more answers
After a 5% pay raise , Hermione is earning $21,000 per year. What was she earning before the pay raise?
zzz [12365]

Answer:

\$20,000

Explanation step-by-step:

Let

x represent Hermione's salary prior to the raise

Given:

100\%+5\%=105\%=105/100=1.05

Therefore, the equation that expresses this relationship is

1.05x=21,000

To find x, divide both sides by 1.05:

x=21,000/1.05

x=\$20,000

7 0
3 months ago
If ABCD is a parallelogram, which of the following statements must be true?
lawyer [12517]

Answer: d. AB = CD and BC = AD


Step-by-step explanation:

A parallelogram is defined as a four-sided figure with the following characteristics:-

  1. Opposite sides are equal (AB = CD and BC = AD ).
  2. Opposite angles are equal (∠A=∠C and ∠D=∠B).
  3. Consecutive angles are supplementary (∠A + ∠D = 180°).
  4. The diagonals bisect one another.
  5. If one angle is a right angle, then all angles are right angles.

8 0
2 months ago
Read 2 more answers
A really bad carton of eggs contains spoiled eggs. An unsuspecting chef picks eggs at random for his ""Mega-Omelet Surprise."" F
Leona [12618]
(a) The likelihood that all 5 eggs chosen are unspoiled is 0.0531. (b) The probability that 2 or fewer out of the 5 eggs are unspoiled is 0.3959. (c) The probability that more than 1 of the selected 5 eggs are unspoiled is 0.8747. Step-by-step explanation: The complete query is: A subpar carton of 18 eggs has 8 that are spoiled. An unsuspecting chef selects 5 eggs at random for his “Mega-Omelet Surprise.” Calculate the probability of receiving (a) exactly 5 unspoiled eggs, (b) 2 or fewer, and (c) more than 1 unspoiled egg. Define X = number of unspoiled eggs. In the faulty carton, 8 eggs are spoiled. The probability of selecting an unspoiled egg is independent of others. Provided that a chef randomly picks 5 eggs, the variable X follows a Binomial distribution with parameters n = 5 and p = 0.556. Success is defined as selecting an unspoiled egg. The probability mass function of X is as follows: (a) Calculate the probability of selecting all unspoiled eggs. Thus, this probability is found to be 0.0531. (b) For 2 or less unspoiled eggs, the probability is computed: P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2), resulting in a probability of 0.3959. (c) For more than 1 unspoiled egg: P (X > 1) = 1 - P (X ≤ 1), yields a final probability of 0.8747.
6 0
2 months ago
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