Toyota and its suppliers have a relationship in which Toyota encourages suppliers to modernize their facilities and provides the

The most suitable choice here is A) They distribute samples and free trials as a way to gauge public interest in their product.
I hope that helps.

Respuesta:

$23,709

Explicación:

Datos proporcionados en la pregunta:

Monto del bono emitido = $700,000

Duración = 5 años

Tasa de interés = 8%

Monto de venta del bono = $728,700

Tasa de interés de mercado = 7%

Ahora,

Intereses pagados = Monto del bono emitido × Tasa de interés

= $700,000 × 0.08

= $56,000

Gasto por intereses = Monto del bono vendido × Tasa de interés de mercado

= $728,700 × 0.07

= $51,009

Prima no amortizada = Monto de venta del bono - Monto del bono emitido

= $728,700 - $700,000

= $28,700

Monto amortizado = Intereses pagados - Gasto por intereses

= $56,000 - $51,009

= $4,991

Balance de la cuenta de primas sobre bonos a pagar inmediatamente después del primer pago de intereses

= prima no amortizada - Monto amortizado

= $28,700 - $4,991

= $23,709

The best answer that would appropriately finalize the statement provided earlier would be the last option. The comprehensive statement indicates cash inflows and outflows that stem from a firm's operational, investment, and financing activities. I hope this explanation proves useful.

Answer:

A. Dr Amortization expense $43,750

Cr Patents $43,750

B. Dr Amortization expense $5,230

Cr Patents $5,230

C. Dr Amortization expense $14,000

Cr Franchises $14,000

Explanation:

Journal entry preparations

A. Dr Amortization expense $43,750

($350,000÷8 years = $43,750)

Cr Patents $43,750

(Recording amortization for the patent)

B. Dr Amortization expense $5,230

($52,300÷10 years = $5,230)

Cr Patents $5,230

(Recording amortization for the patent)

C. Dr Amortization expense $14,000

($70,000÷5 years = $14,000)

Cr Franchises $14,000

(Recording amortization for franchises)

This pertains to permutations, and since we are fixing the first and last joke's positions based on the information provided, there are 10 remaining jokes to arrange. Any unique ordering of these 10 jokes will yield a different configuration, thereby giving us a total of 10! arrangements, which can be calculated as 10! = 10*9*8*7*6*5*4*3*2*1 = 3628800. Thus, there are 3628800 different sequences to present the old joke first and the new joke at the end.