A movie is 1 7/8 hours long. After 45 minutes, how much of the movie is left?

Answer:

Given that the frog jumps every 10 seconds

   (using digits from a random number table)

• It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
• Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
• Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.

Step-by-step explanation:

A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.

Every 10 seconds, the frog jumps left or right.

If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.

If it jumps as LLRLL, it will jump off the board after fifty seconds.

Given that the frog jumps every 10 seconds

   (using digits from a random number table)

• It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
• Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
• Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.

Answer:

D

Step-by-step explanation:

When you multiply 3/4 by A, B, or C, it results in a decimal value; however, multiplying 3/4 by 8 yields 6, which is a whole number.

Jason can confirm the accuracy of his solution by substituting the calculated x value back into the original equation to check if it holds true. If the equality fails, it indicates that his calculated x is incorrect.

Answer:

Shane must have gathered a minimum of 911 cans.

Step-by-step explanation:

Let S represent the number of cans Shane collected.

Since Abha collected 178 more cans, her total is S + 178.

The combined total should be at least 2000:

S + (S + 178) ≥ 2000

2S + 178 ≥ 2000

2S ≥ 2000 - 178

2S ≥ 1822

S ≥ 911

Therefore, Shane must have collected at least 911 cans.

Answer:

For a 90º clockwise rotation, the vertex q' (–3, 4) maps to q(4, 3).

According to the 90º counterclockwise rotation rule, q' (–3, 4) transforms to q(–4, –3).

Step-by-step explanation:

Given the rectangle with vertices r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4),

Find the image of vertex q after a 90º rotation.

The rotation rules are:

90º clockwise: (x, y) → (y, –x)

90º counterclockwise: (x, y) → (–y, x)

Applying the clockwise rule to q'(–3, 4) yields q(4, 3).

Applying the counterclockwise rule to q'(–3, 4) yields q(–4, –3).

Thus, clockwise rotation of q' (–3, 4) results in q(4, 3),

and counterclockwise rotation results in q(–4, –3).