Find the length of the curve. r(t) = 3 i + t2 j + t3 k, 0 ≤ t ≤ 1

Answer:

a) 0.216

b) 0.784

c) 0.288

d) 0.352

e) 0.784

Step-by-step explanation:

The steps for solving this are provided in an image.

Let y represent the gallons of water left in the barrel, and let x represent the minutes that have passed. Water escapes the barrel at a rate of 1 gallon for every 10 minutes. Consequently, the appropriate linear equation for this scenario is shown in the attached graph.

The diagram below illustrates the issue at hand.

Question 1:
The maximum area of the pool equals half the area of the circle.

To calculate the area of the circle: Area = πr², with r being half of the diameter.
Thus, Area of circle = π(60)² = 11309.73355 square feet.

Therefore, the area representing half the circle amounts to 11309.73355/2 = 5654.866... ≈ 5654.87 square feet (rounded to 2 decimal places).

Question b:

To find the pool's area, we take the circle's area and subtract the triangle's area.

The area of the circle is 11309.73 square feet.

For the triangle's area calculation: 1/2 × (60×103.92) = 3117.6 square feet.

The area of the pool thus operates as 11309.73 - 3117.6 = 7922.13 square feet.

Calculating the pool's volume: 7922.13 × 4 = 31688.52 cubic feet.

Note: Information related to the fish tank is unavailable, so the above calculation focuses solely on the entire pool's volume.

The precise distance between the two points is calculated to be 10.

Answer:

The chance of completing the entire package installation in under 12 minutes is 0.1271.

Step-by-step explanation:

We define X as a normal distribution representing the time taken in seconds to install the software. According to the Central Limit Theorem, X is approximately normal, where the mean is 15 and variance is 15, giving a standard deviation of √15 = 3.873.

To find the probability of the total installation lasting less than 12 minutes, which equals 720 seconds, each installation should average under 720/68 = 10.5882 seconds. Thus, we seek the probability that X is less than 10.5882. To do this, we will apply W, the standard deviation value of X, calculated via the formula provided.

Utilizing , we reference the cumulative distribution function of the standard normal variable W, with values found in the attached file.

Given the symmetry of the standard normal distribution density function, we ascertain .

Consequently, the probability that the installation process for the entire package is completed within 12 minutes is 0.1271.