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DanielleElmas
1 month ago
8

Nicholas scoops a few gum balls into his bag when he weighs it he finds that he scooped 0.76 pounds how much will the gum balls

cost show work gum balls $3.48 Nichols has decided to buy 1.5 pounds of sour patch kids how much will the sour patch kids cost sour patch kids $3.99 show work
Mathematics
1 answer:
tester [12.3K]1 month ago
4 0

Response:

The price for 0.76 pounds of gum balls amounts to $2.6448

For 1.5 pounds of sour patch kids, the cost is $5.985

Step-by-step breakdown:

Refer to the provided data.

Nicholas measures a few gum balls into his bag, discovering a total of 0.76 pounds. The price for 1 pound of gum balls is $3.48

Expressed mathematically, this is:

1 pound of gum balls = $3.48

Now, we multiply both sides by 0.76

1×0.76 pounds of gum balls = $3.48×0.76

Thus, 0.76 pounds of gum balls costs $2.6448

Nicholas decides to purchase 1.5 pounds of sour patch kids at $3.99 per poundThis can be represented as:

1 pound sour patch kids = $3.99

We multiply both sides by 1.5

1×1.5 pounds sour patch kids = $3.99×1.5

This leads to a total of 1.5 pounds of sour patch kids costing $5.985

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Let x represent the number of pages in the U.S. Tax Code and y denote the pages in the King James Bible.

According to the provided information,
x= y+18,528 ⇒ y=x-18,528
x+y = 21,472 ⇒ x+(x-18,528) = 21,472 ⇒ x+x-18,528 = 21,472 ⇒ 2x= 18,528+21,472 ⇒ 2x = 40,000 ⇒ x=40,000/2 = 20,000 pages

Therefore, the U.S. tax code consists of 20,000 pages.
6 0
3 months ago
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A home’s value increases at an average rate of 5.5% each year. The current value is $120,000. What function can be used to find
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Answer:

f(x)=120000 \times (1.055)^{x}

Step-by-step explanation:

The present value of the house is $120,000 and the interest rate is 5.5%, or 0.055.

We will utilize the following equation:

f(x)=P \times (1+r)^{x}

where P represents the present value, r symbolizes the interest rate, and x refers to the number of years.

By inputting the values into the above equation, we can obtain:

f(x)=120000 \times (1+0.055)^{x}

f ( x ) = 120000 \times ( 1.055 ) ^ { x }

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2 months ago
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A frog is sitting exactly in the middle of a board that is five feet long. Every ten seconds he jumps one foot to the left or on
PIT_PIT [12445]

Answer:

Given that the frog jumps every 10 seconds

   (using digits from a random number table)

  • It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
  • Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
  • Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.

Step-by-step explanation:

A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.

Every 10 seconds, the frog jumps left or right.

If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.

If it jumps as LLRLL, it will jump off the board after fifty seconds.

Given that the frog jumps every 10 seconds

   (using digits from a random number table)

  • It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
  • Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
  • Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
4 0
3 months ago
For your college interview, you must wear a tie. You own 3 regular (boring) ties and 5 (cool) bow ties. 36 1. Counting (a) How m
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Response:

a) 8

b) 15

c) 34

Detailed explanation:

Section a) Options for neck-wear

Regular ties count = 3

Bow ties count = 5

Overall ties count = 3 + 5 = 8

Any tie can be selected from these 8 available options. Thus, the options for neck-wear total 8.

Section b)

We now calculate choices for using both regular and bow ties.

Selecting a regular tie is independent of the bow tie selection. According to counting principles, if two events are independent, the total ways to realize both equal the product of their individual possibilities. Thus,[

Number of ways to select both ties = Count of ways to choose each tie

So,

Ways for wearing both types of ties = 3 x 5 = 15 ways

Section c)

Count of shirts = 5

Count of skirts = 4

Count of pants = 3

Count of dresses = 7

Choice options for outfits include:

  • Shirt paired with Skirt or Pants
  • Or simply a dress

Pants can be chosen in 3 ways. Pairing a skirt or pant provides 9 options.

Reapplying counting rules:

Ways to wear a shirt with a skirt or pant = 3 x 9 = 27

Choices for dresses = 7

Consequently, the total is 27 + 7 = 34 outfit combinations.

5 0
2 months ago
The sharks are fed three times a day. During the morning feeding , 2/15 tons of fish is fed. During the afternoon feeding, the w
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Answer:

1/6 ton of fish is provided during the night feeding.

Step-by-step explanation:

The fish consumed in the morning is \dfrac{2}{15} tons, and the amount of fish served in the afternoon is \dfrac{1}{15} greater than in the morning. This means

\dfrac{2}{15} +\dfrac{1}{15}

Let’s represent the quantity of fish given at night as x, and if the total fish fed throughout the day equals \dfrac{1}{2}, we have

\dfrac{2}{15}+(\dfrac{2}{15} +\dfrac{1}{15})+x=\dfrac{1}{2}

By summing the numerators on the left side, we derive:

\dfrac{5}{15} +x=\dfrac{1}{2}

and subtracting \dfrac{5}{15} from both sides allows us to isolate x:

x=\dfrac{1}{2} -\dfrac{5}{15}

Since \dfrac{5}{15} =\dfrac{1}{3}, we derive

x=\dfrac{1}{2}-\dfrac{1}{3}

The common denominator for the fractions is 6; hence, we write the equation in the form

x=\dfrac{3}{6}-\dfrac{2}{6}

and simplifying the numerators results in:

\boxed{x=\dfrac{1}{6} }

which indicates the amount of tons fed during the night feeding.

7 0
2 months ago
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