(HELP NEEDED ASAP!!!)The sequence below represents Marisa’s fine at the library for each day that she has an overdue book: $0.50

Question

3 months ago

13

(HELP NEEDED ASAP!!!)The sequence below represents Marisa’s fine at the library for each day that she has an overdue book: $0.50

, $0.65, $0.80, $0.95, $1.10, ... Which equation represents Marisa’s library fine as a function of a book that is n days overdue? f(n) = 0.15n f(n) = 0.50n f(n) = 0.15n + 0.35 f(n) = 0.50n + 0.15

Mathematics

2 answers:

Svet_ta [12.7K] · Answer 1 · 2026-03-03T22:48:06+03:00

Svet_ta [12.7K]3 months ago

7 0

Answer:

F(n)= 0.50+0.15

Step-by-step explanation:

The starting point is 0.50. Additionally, when adding a fine of 0.15, you would consider 0.15 as well.

AnnZ [12.3K] · Answer 2 · 2026-03-03T22:47:54+03:00

Answer:

C. $f(n)=0.15n+0.35$

Step-by-step explanation:

The fines Marisa incurs at the library each day for her overdue book are represented in the sequence: $0.50, $0.65, $0.80, $0.95, $1.10,...

This forms an arithmetic sequence in the structure $a_n=a_1+(n-1)d$ , where $a_n$ represents the n-th term.

$a_1$ denotes the first term of this sequence.

d= represents the common difference.

Observing the sequence, the first term is identified as 0.50.

To find the common difference, subtract 0.50 from 0.65.

$\text{Common difference}=0.65-0.50=0.15$

By inserting our established values into the arithmetic sequence formula, we can derive,

$f(n)=0.50+(n-1)0.15$

Distributing the 0.15 gives us,

$f(n)=0.50+0.15n-0.15$

Now we can consolidate like terms.

$f(n)=0.15n+0.50-0.15$

$f(n)=0.15n+0.35$

Consequently, the equation $f(n)=0.15n+0.35$ accurately represents Marisa’s overdue library fine as a function of the number of days n, confirming that option C is indeed correct.