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WARRIOR
17 days ago
6

Q13. A stone is dropped from a height of 5 km. The distance it falls through varies directly with the

Mathematics
2 answers:
Leona [4.1K]17 days ago
8 0
I’m not really certain, but I think C could be the answer; my apologies if that's inaccurate.
zzz [4K]17 days ago
3 0

Answer:

During the 5th second, the stone travels 36 meters. The correct answer is A.

Step-by-step explanation:

Proportions

Two quantities are considered proportional if one can be derived from the other by multiplying by a constant. If we denote these variables as y and x, it can be expressed as:

y=k.x

There are other forms of proportions where the relationship is non-linear. For example, if y varies with the square of x, we can represent this as:

y=k.x^2

According to the problem's parameters, the distance a stone drops from a height of 5 km is directly proportional to the square of the time taken during the descent. If d denotes the distance and t indicates time, we have:

d=k.t^2

To determine the constant k, we apply the provided information: the stone falls d=66 meters in t=4 seconds. By substituting:

64=k.4^2=16k

Solving this yields:

k=64/16=4

Using the value of k in the equation completes the model.

d=4.t^2

Next, we calculate the distance after t=5 seconds:

d=4\cdot 5^2=4\cdot 25=100

After 5 seconds, the stone has traveled 100 meters. However, we need the distance for just the 5th second, specifically between 4 and 5 seconds.

We already know the distance at t=4 seconds is 64 meters and at t=5 seconds it's 100 meters:

distance in the 5th second = 100 m - 64 m = 36 m

The stone covers 36 m in the 5th second. Select option A.

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