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miss Akunina
14 days ago
8

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

P(t) denote the number of people (in millions) who become aware of the product by time t. Suppose that P increases at a rate proportional to the number of people still unaware of the product. The company determines that no one was aware of the product at the beginning of the campaign, and that 50% of the people were aware of the product after 50 days of advertising. The number of people who become aware of the product at time t is:
Mathematics
1 answer:
PIT_PIT [9.1K]14 days ago
5 0
Step-by-step explanation: Since the number P(t) increases proportionally to the number of individuals unaware of the product, we establish that initially, nobody is aware of the product at the campaign's start and that 50% are aware after 50 days of advertisements. Thus, we determine: P(0) = 0 and P(50) = 1,500,000, leading to a first-order ordinary differential equation. The integrating factor must be calculated and both sides of the equation manipulated accordingly. Hence, upon integrating and solving, we arrive at the equation modeling the number of people (in millions) aware of the product over time.
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Draw a diagram in which segment AB intersects segment CD equals segment CB
lawyer [9240]
The correct illustration is provided.

Explanation:

Utilizing a tool like Geogebra, commence by creating a line segment. Label the endpoints as C and D.

Next, draw the perpendicular bisector of the segment and denote the intersection with CD as B, then introduce a point A above this line.

Measure the distance from C to B and from B to D. Both distances will be equal.

Measure the length from A to B. If this distance is not equal to that from C to B, adjust A along line AB until the distances match.

With a compass and straightedge:

First, create segment CD and ensure the endpoints are labeled.

Adjust your compass to slightly more than half the distance between C and D. With it set at C, draw an arc above CD.

Using the same compass setting at D, draw another arc to intersect your first arc above CD. Mark the intersection as E.

Connect E to CD with a straightedge and label the intersection as B.

Set your compass to the distance from C to B. Position it on B and mark an arc on EB. Designate this intersection point as A.

Thus, AB will equal both CB and BD.

5 0
1 month ago
Read 2 more answers
Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number is equal to twice the smalle
AnnZ [9099]

Answer:

y = negative four-thirds x + StartFraction 31 Over 3 EndFraction

y = 2 x + 7

Step-by-step explanation:

Let x denote the smaller number and y denote the larger number.

Part 1

The equation presented indicates that four times some number added to three times a larger number equals 31.

This translates to:

  • 4x + 3y = 31

From here, solving for y yields:

  • 4x + 3y=31 ⇒ 3y= -4x+31 ⇒ y= (-4x+31)/3 = - 4/3x + 31/3

    ⇒  y= - 4/3x + 31/3

This indicates the correct response for this scenario:

y = negative four-thirds x + StartFraction 31 Over 3 EndFraction

Part 2

The statement that seven subtracted from the larger number equals twice the smaller number translates to:

y-7= 2x

Further, solving for y yields:y-7= 2x ⇒

y= 2x+ 7

The correct answer for this equation is:

y = 2 x + 7
4 0
7 days ago
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Zina [9171]

Answer:

Step-by-step reasoning:

(a)

To have an accepted bid, it needs to exceed $10,000. Let bid x be a continuous random variable uniformly distributed between

$10,000 and $15,000

The range for accepted bidding is [ {\rm{\$ 10,000, \$ 15,000}], with b = $15000 and a = $10000.

The provided bidding range is [$10,000,$12,000]. The probability is determined as follows,

\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}

=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4

(b)  The accepted bidding range is [$10,000,$15,000], where b = $15,000 and a =$10,000. The given bidding range is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

The optimal amount to bid for maximizing the probability of acquiring the property is calculated as,  

The accepted bidding range is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The provided bidding range is [$10,000,$15,000].

\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}

(d)  If you know someone willing to pay you $16,000 for the property, would you still consider bidding less than the amount mentioned in part (c)? Why or why not?

5 0
5 days ago
Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road oriented at an angle of 25
PIT_PIT [9117]

Answer:

6.79 miles

Step-by-step explanation:

Consider triangle ABC where A marks the starting point and C indicates the end point.

|AB|=5.2 miles

|BC|=3.0 miles

∠ABC = 90 + 75 = 165°

We're given two side lengths and an angle that is not opposite to either side.

The approach to resolve this scenario is known as the Cosine Rule.

Each side opposite an angle is designated by the corresponding lowercase letter.

The Cosine Rule asserts that:

b² = a² + c² - 2acCosB

|AC|²=3² + 5.2² - (2 × 5.2 × Cos 165°)

|AC|²=9 + 27.04 + 10.05

|AC|²=46.09

|AC|=√46.09=6.79 miles

Thus, the straight-line distance from A to C measures 6.79 miles

8 0
1 month ago
A high school theater club has 40 students, of whom 6 are left-handed. Two students from the club will be selected at random, on
babunello [8412]

Response:

1.92\%

Detailed explanation:

Probability for an event is calculated as the ratio of the size of the event space compared to that of the sample space.

The sample space encompasses all possible outcomes.

Event space represents the number of favorable outcomes for the event in question.

Thus

Let

x ------> size of event space

y ----- → size of sample space

so

P=\frac{x}{y}

Calculate the probability of the first student being left-handed

we have

x=6

y=40

substituting values

P=\frac{6}{40}

Simplify

P=\frac{3}{20}

Calculate the probability of the second student being left-handed

we have

x=6-1=5

y=40-1=39

substituting values

P=\frac{5}{39}

Calculate the probability that both selected students will be left-handed

Multiply the probabilities together.

P=\frac{3}{20}(\frac{5}{39})=\frac{15}{780}

Convert to percentage

Multiply by 100

\frac{15}{780}(100)=1.92\%

4 0
27 days ago
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