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Lisa
3 months ago
9

In three hours, Company ABC can make X ball bearings. Company DEF can make X ball bearings in 4 hours. Company GHI can make X ba

ll bearings in 6 hours. Working together, how long will it take all three companies to make X ball bearings?
Mathematics
1 answer:
AnnZ [12.3K]3 months ago
8 0

Answer:

X ball bearings can be produced in 1 hour and 20 minutes

Step-by-step explanation:

Proportions

Proportions serve as an essential method for solving various common challenges. We understand that:

Company ABC manufactures X ball bearings in 3 hours.

Company DEF produces X ball bearings in 4 hours.

Company GHI generates X ball bearings in 6 hours.

In a single hour, each company is capable of producing:

ABC: X/3 ball bearings

DEF: X/4 ball bearings

GHI: X/6 ball bearings

By collaborating, they can produce

\displaystyle \frac{X}{3}+\frac{X}{4}+\frac{X}{6}

ball bearings. Operating together

\displaystyle \frac{4X+3X+2X}{12}=\frac{9X}{12}=\frac{3X}{4}

If their output is 3/4 of a ball bearing in one hour, then it will take

\displaystyle \frac{4}{3} hours to create one complete ball bearing. This translates to 1 hour and 20 minutes.

X ball bearings can be produced in 1 hour and 20 minutes

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babunello [11817]

We start with

x^2y-2xy-24y=y(x^2-2x-24)

Next, we can factor out the term on the right side

x^2-2x-24=x^2-6x+4x-6*4

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Now, we will substitute back

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So,

x^2y-2xy-24y=y(x-6)(x+4).............Response

5 0
2 months ago
Read 2 more answers
for the level 3 course, examination hours cost twice as much as workshop hours and workshop hours cost twice as much as lecture
Leona [12618]

Answer:

The hourly rate for lectures is $7.33

Step-by-step explanation:

* Let's break down how to tackle the problem.

- For the level 3 course, examination hours are priced at double that of workshop hours.

- Workshop hours cost twice the rate of lecture hours.

- The total includes examination, workshop, and lecture hours.

- Examination lasts 3 hours, workshops 24 hours, and lectures 12 hours.

* Let’s denote the cost of lecture hours as $x per hour.

∴ The lectures cost $x per hour.

∵ Workshop charge is twice that of lectures

∴ Workshop hours cost 2(x) = 2x per hour.

∵ Examination fees are double that of workshop hours

∵ The workshop cost is 2x

∴ Examination fees are 2(2x) = 4x per hour.

- Combining costs for level 3 gives us the total of lecture, workshop, and examination hours.

∵ 12 hours for lectures

∵ 24 hours for workshops

∵ 3 hours for examinations

∵ Thus the total cost for level 3 = 12(x) + 24(2x) + 3(4x).

∴ Total cost for level 3 = 12x + 48x + 12x.

∵ Therefore, total cost = $528.

∴ 12x + 48x + 12x = 528.

∴ 72x = 528; hence we divide both sides by 72.

∴ x = 7.33.

∵ x represents the cost of lecture hours per hour.

∴ Therefore, the hourly price for lectures is $7.33.

6 0
3 months ago
A student is deriving the quadratic formula. Her first two steps are shown. Step 1: –c = ax2 + bx Step 2: -c = a[x^2+b/ax] Which
Svet_ta [12734]

The options presented are:

(1) division property of equality

(2) factoring the binomial

(3) completing the square

(4) subtraction property of equality

Response: (2) factoring the binomial

Step 1: -c = ax^2 + bx

Step 2:-c = a[x^2+\frac{b}{a} x]

In step 2, 'a' is extracted from ax^2 + bx. Upon factoring out 'a', we divide all terms by 'a', resulting in a[x^2+\frac{b}{a} x].

Step 2 involves the binomial factorization process.



6 0
3 months ago
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