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horrorfan
3 months ago
5

Mike has coffee worth $4 per pound that he wishes to mix with 20 pounds of coffee worth $7 per pound to get a mixture that can b

e sold for $5 per pound. How many pounds of the cheaper coffee should he use?
Mathematics
1 answer:
lawyer [12.5K]3 months ago
5 0
\bf \begin{array}{lccclll}
&\stackrel{lbs}{amount}&\stackrel{per~lb}{price}&\stackrel{amount}{price}\\
&------&------&------\\
\textit{\$4/lb coffee}&x&4&4x\\
\textit{\$7/lb coffee}&20&7&140\\
------&------&------&------\\
mixture&y&5&5y
\end{array}

We know the blend consists of both coffee types, thus x + 20 = y, and 4x + 140 = 5y.

\bf \begin{cases}
x+20=\boxed{y}\\
4x+140=5y\\
----------\\
4x+140=5\left( \boxed{x+20} \right)
\end{cases}
\\\\\\
4x+140=5x+100\implies 140-100=5x-4x\implies 40=x
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