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1 month ago

Customer: “What can I do to decrease my bill by $25.00 per month?”

2 answers:

5 0

I believe the solution is $83.33.

Calculating 25 by 30%, or 25 divided by 0.3, gives approximately 83.3333.

You can verify this by calculating the discount amount based on the previous figure.

$83.33 multiplied by 0.3 equals about $24.999, rounding to $25.

Therefore, the package with a 30% discount would save the customer $25 monthly.

Inessa [12.5K]1 month ago

5 0

The customer’s monthly bill approximately amounts to $35.70. By multiplying 35.70 by 0.70 (30% as a decimal), you find 24.99, which is the target amount he aims for now.

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According to Consumer Digest (July/August 1996), the probable location of personal computers (PC) in the home is as follows: Adu

PIT_PIT [12445]

Answer:

a) 0.32

b) 0.68

c) Office or den

Step-by-step explanation:

a) The likelihood that a personal computer is located in a bedroom can be calculated by adding the probabilities of it being in an adult bedroom, child bedroom, or another bedroom:

$P(B) =P(adult)+P(child)+P(other)\\P(B) = 0.03+0.15+0.14\\P(B) =0.32$

b) The probability of a PC not being located in a bedroom is found by calculating 100% minus the probability of it being in a bedroom:

$P(Not\ B) = 1- P(B)\\P(Not\ B) =1-0.32\\P(Not\ B) =0.68$

c) The expected location for finding a personal computer in a randomly selected household is derived from the room most likely to contain a PC according to Consumer Digest. The Office or den ranks as the most likely place with a probability of 0.40.

A PC would most likely be found in the Office or den.

6 0

1 month ago

Consider the next 1000 98% CIs for μ that a statistical consultant will obtain for various clients. Suppose the data sets on whi

lawyer [12517]

Answer:

d) Both blocks experienced equivalent energy loss due to friction

Explanation:

As stated in the question, two tractors are pulling two identical stone blocks the same distance across similar surfacesAdditionally, block A moves at double the speed of block B when completing the race

This implies both blocks suffer from comparable friction loss

Moreover, we understand that

Energy loss from friction is $E(X) = np$

Thus, the friction loss should be identical for both blocks

therefore, option d is the accurate choice $p = 0.98$

6 0

24 days ago

Determine the multiplicity of the roots of the function k(x) = x(x + 2)3(x + 4)2(x − 5)4. 0, -2, -4, 5

zzz [12365]

Answer:

The polynomial expression $k(x)=x(x+2)^3(x+4)^2(x-5)^4$

To ascertain the multiplicity of 0, -2, -4, 5.

The multiplicity refers to how many times a root appears in a function.

First, identify the function's roots by setting it to zero.

$x(x+2)^3(x+4)^2(x-5)^4=0$

Thus, the roots are x=0, -2, -4, and 5

To determine the roots' multiplicities:

The factor of x will give a root of x=0 with a multiplicity of 1

likewise, x=-2 with a multiplicity of 3

x=-4 with a multiplicity of 2

and x=5 with a multiplicity of 4.

4 0

1 month ago

Read 2 more answers

The mean diameter of the rim of Honda tires is 16 inches. Assume that the standard deviation of diameter of the rims is 0.3 inch

Leona [12618]

Sagot:

a. 0.0124 = 1.24% ang posibilidad na itigil ang paggawa kapag ang sample mean ay 16 inches.

b. 0.0241 = 2.41% ang posibilidad na itigil ang paggawa kung ang mean ay lumipat sa 16.05 inches.

c. 0.5 = 50% ang posibilidad na hindi makagambala sa produksyon kung ang mean ay lumipat sa 16.25 inches.

Hakbang-hakbang na paliwanag:

Upang masagot ang tanong na ito, kinakailangan nating maunawaan ang normal probability distribution at ang central limit theorem.

Normal probability distribution

Kapag ang distribusyon ay normal, ginagamit natin ang z-score formula.

Sa isang set na may mean $\mu$ at standard deviation $\sigma$ , ang z-score ng sukat X ay ibinibigay ng:

$Z = \frac{X - \mu}{\sigma}$

Ang Z-score ay sumusukat kung gaano karaming standard deviations ang sukat ay mula sa mean. Pagkatapos makuha ang Z-score, titingnan natin ang z-score table at hahanapin ang p-value na kaugnay ng z-score na ito. Ang p-value na ito ay ang posibilidad na ang halaga ng sukat ay mas maliit kaysa sa X, na ibig sabihin ay ang percentile ng X. Sa pamamagitan ng pagbawas ng 1 sa p-value, makakakuha tayo ng posibilidad na ang halaga ng sukat ay mas mataas sa X.

Central Limit Theorem

Itinataguyod ng Central Limit Theorem na, para sa isang normal na ipinamamahaging random variable X, na may mean $\mu$ at standard deviation $\sigma$ , ang sampling distribution ng sample means na may sukat n ay maaaring i-approximate sa isang normal na distribusyon na may mean $\mu$ at standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

Ipagpalagay na ang standard deviation ng diameter ng mga rims ay 0.3 inches. Ang samples ay 9.

Ibig sabihin nito $\sigma = 0.3, n = 9, s = \frac{0.3}{\sqrt{9}} = 0.1$

a. Kalkulahin ang posibilidad na itigil ang paggawa kapag ang sample mean ay 16 inches.

$\mu = 16$ Narito ang

Mas mataas sa 16.25:

Ito ay 1 na ibinawas mula sa p-value ng Z kapag X = 16.25. Kaya

$Z = \frac{X - \mu}{\sigma}$

Sa pamamagitan ng Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{16.25 - 16}{0.1}$

$Z = 2.5$

$Z = 2.5$ may p-value na 0.9938

1 - 0.9938 = 0.0062

Mas mababa sa 15.75:

Ito ay p-value ng Z kapag X = 15.75. Kaya

$Z = \frac{X - \mu}{s}$

$Z = \frac{15.75 - 16}{0.1}$

$Z = -2.5$

$Z = -2.5$ may p-value na 0.0062

Probabilidad ng pagtigil:

2*0.0062 = 0.0124

0.0124 = 1.24% ang posibilidad na itigil ang paggawa kapag ang sample mean ay 16 inches.

b. Kalkulahin ang posibilidad na itigil ang paggawa kung ang mean ay lumipat sa 16.05 inches.

$\mu = 16.05$

Narito ang

Mas mataas sa 16.25:

$Z = \frac{X - \mu}{s}$

$Z = \frac{16.25 - 16.05}{0.1}$

$Z = 2$

may p-value na 0.9772

1 - 0.9772 = 0.0228

Mas mababa sa 15.75:

Ito ang p-value ng Z kapag X = 15.75. Kumbaga

$Z = \frac{X - \mu}{s}$ may p-value na 0.0013

$Z = \frac{15.75 - 16.05}{0.1}$

$Z = -3$

$Z = -3$ Probabilidad ng pagtigil:

0.0228 + 0.0013 = 0.0241

0.0241 = 2.41% ang posibilidad na itigil ang paggawa kung ang mean ay lumipat sa 16.05 inches.

c. Kalkulahin ang posibilidad na hindi makagambala sa produksyon kung ang mean ay lumipat sa 16.25 inches.

Sa pagitan ng 16.25 at 15.75 na may $\mu = 16.25$ . Ito ang p-value ng Z kapag X = 16.25 na ibinawas mula sa p-value ng Z kapag X = 15.75.

X = 16.25

$Z = \frac{X - \mu}{s}$

$Z = \frac{16.25 - 16.25}{0.1}$

$Z = 0$

$Z = 0$ may p-value na 0.5

X = 15.75

$Z = \frac{X - \mu}{s}$

$Z = \frac{15.75 - 16.25}{0.1}$

$Z = -5$

$Z = -5$ may p-value na 0

0.5 - 0 = 0.5

0.5 = 50% ang posibilidad na hindi makagambala sa produksyon kung ang mean ay lumipat sa 16.25 inches.

3 0

15 days ago

Which equation is y = 6x2 + 12x – 10 rewritten in vertex form?

lawyer [12517]

Y = 6 x² + 12 x - 10. Factor out the 6 to get 6 ( x² + 2 x ) - 10. Rewrite the quadratic by adding and subtracting 1 inside the parentheses: 6 ( ( x² + 2 x + 1 ) - 1 ) - 10.
This reduces to 6 ( x + 1 )² - 6 - 10 = 6 ( x + 1 )² - 16 ( vertex form)

5 0

1 month ago

Read 2 more answers