Metal Melting Point (°C) Boiling Point (°C) Density in Solid State (g/cm3) Copper 1,083 2,567 8.3–9.0 Lead 327.3 1,750 11.3 Gold

Could you please clarify? I can't perform any calculations without knowing where this figure is and its dimensions - 

The area of square TUVW is calculated as 3 times 3, giving 9 square units.

In terms of head lettuces, since 1 square unit accommodates 4 lettuces, 9 square units can house 9 times 4, totaling 36 lettuces.

For plot QRST, the area is determined by multiplying its length by its width: 12 times 6 equals 72 square units.

With 36 vegetables available for every 9 square units, we can partition 72 by 9 to yield 8 plots of 9 square units.

In total, this accounts for 8 times 36, resulting in 288 vegetables.

We can cultivate 8 types of vegetables, with each type yielding 36 vegetables.

Answer:

There are 9 essay questions.

Step-by-step explanation:

Let x represent the number of multiple-choice questions and y represent the number of essay questions.

Given that the total question count is 26, we can derive the equation,

Additionally, the multiple-choice and essay questions carry values of 3 points and 8 points, respectively.

The overall points available in the test equal 123.

Thus, we set up the following equations:

x+y=26...........................(1)

3x+8y=123............................(2)

If we multiply equation (1) by 3 and subtract equation (2), we obtain:

5y = 45, leading to y = 9

Consequently, from x+y=26, we find x = 26 - y, resulting in x = 17.

Hence, the counts of multiple-choice and essay questions are 17 and 9, respectively.

The answer is twelve ten thousands. To find how many ten thousands are in 120,000, we recognize that ten thousand equals 10,000. Dividing 120,000 by 10,000 yields 12, meaning there are twelve ten thousands in 120,000. I hope this is helpful, and let me know if you need more assistance!

Answer:

Due to the drawing measuring 200 ft., which translates to 13.33 in. with a scale of 15 ft to 1 in., and given that the sheet of paper is 11 in. long, Adoncia's depiction will not fit onto the paper.

Step-by-step explanation:

The provided details include;

The scale is 15 ft = 1 in.

The actual monument's dimensions;

Height = 80 ft.

Length = 200 ft.

Hence, we can establish;

The necessary paper height = 80/15 = 16/3 = 5.33 in.

The necessary paper length = 200/15 = 40/3 = 13.33 in.

As the paper size provided is 11 in., which is standard at 8.5 in. by 11 in.,

The drawing length of 13.33 in. exceeds the available paper length of 11 in.

Thus, Adoncia's drawing will not fit on the paper.