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Vikki
22 hours ago
10

A 20-ounce candle is expected to burn for 60 hours. A 12-ounce candle is expected to burn for 36 hours. Assuming the variables a

re directly related, how many hours would a 9-ounce candle be expected to burn? 18
Mathematics
2 answers:
zzz [4K]22 hours ago
5 0
La proporción de ambas velas es 20/60, que simplificada es 1/3, por lo que debes tomar la cantidad de onzas que tiene la vela y dividirla por 1/3. Dicho de otra manera: 9 / 1/3 => 9 * 3 = 18
lawyer [4K]22 hours ago
3 0

Respuesta:  Una vela de 9 onzas tiene una duración esperada de 27 horas.

Explicación paso a paso:  Considerando que una vela de 20 onzas se le atribuye durabilidad de 60 horas y una de 12 onzas de 36 horas.

<psi los="" variables="" est="" directamente="" relacionados="">necesitamos hallar el número de horas que una vela de 9 onzas debe durar.

Definamos x como la cantidad de onzas de la vela y y como el número correspondiente de horas que arde.

Dado que los variables son directamente proporcionales, el gráfico generará una línea recta.

Los puntos (x, y) = (20, 60) y (12, 36) se encuentran en dicha línea.

Por lo tanto, la pendiente de la línea será

m=\dfrac{36-60}{12-20}\\\\\\\Rightarrow m=\dfrac{-24}{-8}\\\\\Rightarrow m=3.

Por lo tanto, la ecuación correspondiente es

y-36=m(x-12)\\\\\Rightarrow y-36=3(x-12)\\\\\Rightarrow y=3x.

Así, si x = 9, entonces

y=3\times9=27.

Por consiguiente, una vela de 9 onzas se prevé que dure 27 horas.

</psi>
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Answers:

C - The value of w cannot be negative.

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16 days ago
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zzz [4022]

Answer:

The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction

Step-by-step explanation:

In order to simplify the expression \frac{3x^{-6}y^{-3} }{15x^{2}y^{10} } where x ≠ 0, y ≠ 0, we must work through the given expression.

\frac{3x^{-6}y^{-3} }{15x^{2}y^{10} }\\= \frac{3}{15} x^{-6-2}y^{-3-10}\\ = \frac{3}{15}x^{-8}y^{-13} \\ =\frac{1}{5}x^{-8}y^{-13} \\

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6 0
7 days ago
The temperature, H, in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by H = f(t), where t is in min
Leona [4166]

Response:

a

    f'(t) is negative

b

 The unit is degC/min

c

At 35 minutes since the coffee was placed on the counter, the temperature is 68, and it will drop by approximately 0.75 in the next 30 seconds.

Detailed explanation:

According to the question, we are informed that

   The temperature of a cup of coffee on a counter is represented by the equation

         H= f(t)

where t indicates the time in minutes since the coffee was set on the counter.

In general, f(t)' denotes the derivative of f(t), indicating the change in temperature over time for the coffee

As the coffee rests on the counter, its temperature tends to decrease after a few minutes; thus, f(t)' is negative.

The temperature is measured in degrees Celsius while time is expressed in minutes.

Therefore, the change in temperature with respect to time, f(35)', will be given in degrees Celsius per minute (i.e., degC/min).

The question states that

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which means the rate of temperature change after 35 minutes is 1.5.

And

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indicating that the coffee's temperature after 35 minutes is 67 degrees Celsius.

Subsequently, after another t= 30 seconds = \frac{30}{60}= 0.5 \ minutes the rate at which the coffee's temperature changes is

          R = |f(35)'| * t

=>        R = 1.5 * 0.5

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8 days ago
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