First, combine the solution and salt: 120 liters + 80 liters = 200 liters. The percentages average out: 5% + 15% = 20%. Therefore, the ratio is 20:200, leading to a concentration calculation of 20/200 = 0.10. Ultimately, the final concentration is 10% salt.
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The answer is:
669/221
Discussion:
The ratio of 669 to 221 equals 669/221. Observing the factors, 669 is 3 * 223 and 221 is 13 * 17. As all these factors are distinct primes, nothing cancels in their ratio. Thus, 669/221 remains in its simplest form.
Answer:
50 Educators
Step-by-step explanation:
To tackle this question, the initial step is to calculate the amount of teachers prior to the addition of new staff. For this, I devised Model 1. In this model, teachers are positioned at the top of the ratio and students at the bottom. The variable X represents the number of teachers we are determining. Utilizing this model, I computed 2,100 multiplied by 1 (2,100) and then divided by 14 to conclude there were 150 teachers. Next, I formed a similar model with the updated student-teacher ratio (Model 2). This time, I multiplied 2,100 by 2 (which is 4,200) and divided by 21 to ascertain there are 200 teachers. Having established both the initial and the increased counts of educators, subtracting the original from the new gives you the tally of new teachers, which results in an increase of 50 teachers.
P(S) = Probability of Smash = 0.05 (5%)
P(M) = Probability of Modest = 0.5 (50%)
P(F) = Probability of Flop = 0.45 (45%)
Based on this, we utilize the model for discrete random variables, leading to:
E(X) = (0.05 * 5.2) + (0.5 * 0.9) + (0.45 * 0)
= 0.26 + 0.45 + 0
= 0.71 Mill'