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yanalaym
3 months ago
10

The graph shows the linear relationship between the height of a plant (in centimeters) and the time (in weeks) that the plant ha

s been growing. Which statements are correct? Check all that apply. The rate of change is 4. The rate of change is 1. The rate of change is . The plant grows 4 cm in 1 week. The plant grows 1 cm in 4 weeks

Mathematics
2 answers:
Svet_ta [12.7K]3 months ago
8 0

Answer:

A. The slope equals 4, C. The slope equals 4/1, and D. The plant increases by 4 cm every week.

Step-by-step explanation:

It was exactly at the boundary

babunello [11.8K]3 months ago
5 0
I located a graph that matches this problem, so I assume this is the one to reference. To find the rate of change, calculate the slope between two points on the line, such as (30,10) and (50,20).

Slope = (20 - 10) / (50 - 30) = 10/20 = 1/2

Thus, the rate of change is 0.5 cm per week, or equivalently, 1 cm every 2 weeks.

You might be interested in
Nandini makes 'halwa' one evening and divides it into four equal portions for her family of four. However, just as they are abou
zzz [12365]

Answer:

5%

Step-by-step explanation:

With four individuals, each receives 25% of the halwa. Yet, when a fifth individual joins, each share drops to 20%. Consequently, the original four individuals experience a 5% reduction in their servings due to the new arrival.

4 0
3 months ago
A waterbed filled with water has the dimensions 8ft by 7 ft by .75 ft taking the density of water to be 1.00/gm cubed how many k
Svet_ta [12734]

Density can be defined as:

D = \frac{m}{V}

Where:

m is mass

V stands for volume

To isolate the mass, we derive:

m = DV

Volume can be expressed as:

V = (8) * (7) * (0.75)

V = 42ft ^ 3

We then use the following conversion:

1foot = 0.3048m

After applying the conversion, we arrive at:

V = 42 * (0.3048) ^ 3

V = 1.19m ^ 3

Additionally, we have these conversions:

1m = 100cm

1Kg = 1000g

When we apply these conversions for density, we conclude:

D = (1\frac{g}{cm^3})((\frac{100}{1})^3\frac{cm^3}{1m^3})(\frac{1}{1000}\frac{Kg}{g})=1000\frac{Kg}{m^3}

Finally, the mass of the water required is:

m = (1000) * (1.19)

m = 1190

Answer:

A total of 1190 kilograms of water is needed to fill the waterbed.

7 0
3 months ago
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