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lisabon 2012
4 months ago
9

A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1

), p'(–3, 1), and q'(–3, 4). what is the location of q?
Mathematics
2 answers:
tester [12.3K]4 months ago
6 0
I'm quite certain the answer is:
D. (4, 3)
Please confirm if this is correct!
Svet_ta [12.7K]4 months ago
4 0

Answer:

For a 90º clockwise rotation, the vertex q' (–3, 4) maps to q(4, 3).

According to the 90º counterclockwise rotation rule, q' (–3, 4) transforms to q(–4, –3).

Step-by-step explanation:

Given the rectangle with vertices r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4),

Find the image of vertex q after a 90º rotation.

The rotation rules are:

90º clockwise: (x, y) → (y, –x)

90º counterclockwise: (x, y) → (–y, x)

Applying the clockwise rule to q'(–3, 4) yields q(4, 3).

Applying the counterclockwise rule to q'(–3, 4) yields q(–4, –3).

Thus, clockwise rotation of q' (–3, 4) results in q(4, 3),

and counterclockwise rotation results in q(–4, –3).

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The weight of an orangutan is 64.5 kilograms

Solution:

It is stated that the orangutan's weight is 142 pounds

Additionally,

1 kilogram is approximately 2.2 pounds

We will now convert 142 pounds into kilograms

1 kilogram = 2.2 pounds

\text{1 pound } = \frac{1}{2.2} \text{ kilograms }

As a result, 142 pounds translates to

142 \text{ pound } = \frac{1}{2.2} \times 142 \text{ kilogrmas }

\rightarrow \frac{1}{2.2} \times 142 = 64.545 \text{ kilograms }

When rounding to the nearest tenth, we obtain 64.5 kilograms

Therefore the mass of the orangutan is 64.5 kilograms

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100 plus 70 equals 170

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