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son4ous
1 month ago
12

Which set of ordered pairs represents a function?

Mathematics
2 answers:
PIT_PIT [12.4K]1 month ago
5 0

Answer:

{(3, –1), (7, 1), (–6, –1), (9, 1), (2, –1)}

Step-by-step explanation:

For the given collection to be classified as a function, each x-coordinate must correspond to just a single y-coordinate, meaning each x-value must have a distinct y-value.

In this instance, the image illustrates the graphical depiction of each set, distinguished by color.

{(2, –2), (1, 5), (–2, 2), (1, –3), (8, –1)}  -> Green points

{(3, –1), (7, 1), (–6, –1), (9, 1), (2, –1)}  -> Blue points

{(6, 8), (5, 2), (–2, –5), (1, –3), (–2, 9)}  -> Black points

{(–3, 1), (6, 3), (–3, 2), (–3, –3), (1, –1)} -> Red points

The graph reveals that the only set possessing a single y-value for each x-value is the second one (Blue points).

lawyer [12.5K]1 month ago
5 0

A function is defined as a relationship where every element from the set of first components in ordered pairs correlates to exactly one element from the set of second components.

{(2, –2), (1, 5), (–2, 2), (1, –3), (8, –1)} - this is a function

{(3, –1), (7, 1), (–6, –1), (9, 1), (2, –1)} - this is also a function

{(6, 8), (5, 2), (–2, –5), (1, –3), (–2, 9)} - this represents a function

{(–3, 1), (6, 3), (–3, 2), (–3, –3), (1, –1)} - this does not qualify as a function

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Which fraction is equivalent to StartFraction 2 Over 6 EndFraction? StartFraction 3 Over 7 EndFraction, because StartFraction 2
babunello [11817]
Which equivalent fraction corresponds to \frac{2}{6}? - \frac{3}{7} since \frac{2}{6}= \frac{2 + 1}{6 + 1} - \frac{3}{9} as \frac{2}{6}= \frac{1}{3} and \frac{1}{3} = \frac{3}{9}

- \frac{3}{12} because \frac{2}{6}= \frac{1}{3} and \frac{1}{3} = \frac{3}{9}

- \frac{3}{8} since \frac{2}{6}= \frac{1}{2} = \frac{2+1}{6+2} = \frac{3}{8}

The answer is

- \frac{3}{9} because \frac{2}{6}= \frac{1}{3} and \frac{1}{3} = \frac{3}{9}

A fraction is deemed equivalent if it maintains the same value when expressed in simplest terms. The equivalent to \frac{2}{6} is found in the chosen option;

First, halve both the numerator and denominator by 2

\frac{2/2}{6/2}

Then reduce further

2/2 = 1 and 6/2 = 3; Thus;

\frac{2/2}{6/2} = \frac{1}{3}

Next, multiply both the numerator and denominator by 3

\frac{1*3}{3*3} = \frac{3}{9}

Therefore, \frac{2}{6} equals \frac{3}{9}.

7 0
24 days ago
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Solve X-9+2wx=y for x
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X - 9 + 2wx = y Add 9 to both sides of the equation to isolate terms. Next, you get x + 2wx = y + 9. After that, factor out x to obtain x (1 + 2w) = y + 9. Lastly, divide every term by (1 + 2w) yielding x = (y + 9) / (1 + 2w).
8 0
1 month ago
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Mr.Rowley has 16 homework papers and 14 exit tickets to return. Ms. Rivera has 64 homework papers and 60 exit tickets to return.
Svet_ta [12734]
Mr. Rowley
16:14

Ms. Rivera
64:60

Upon simplifying 64:60, it becomes 16:15.
64/4 = 16
60/4 = 15

They are not equivalent since Ms. Rivera holds 1 more exit ticket than Mr. Rowley.
8 0
18 days ago
Ten liters of pure water are added to a 50-liter pot of soup that is 50% broth. Fill in the missing parts of the table.
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Answer:

c= 25

d= 60

Step-by-step explanation:

C: This is because 25+0 is simply 25. Essentially, you are not adding anything, so it remains unchanged!:)

D: 50 + 10 = 60. That’s straightforward addition!

Hope this helps!

3 0
1 month ago
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Claire is a manager at a toy packaging company. The company packs 80 boxes of toys every hour for the first 3 hours of the day.
Svet_ta [12734]

Response:

Refer to the figure attached.

Step-by-step explanation:

Each portion is treated as a function.

Let x represent the hours worked in a day

The company packs 80 boxes of toys each hour during the first three hours. Thus, y₁ = 80x, for x ∈ [0,3]

After three hours, the total boxes packed = 80 * 3 = 240

They pause packaging for two hours for a training session. Therefore, y₂ = 240, for x ∈ [3,5]

Next, for the subsequent four hours, they pack 20 boxes of toys hourly

y₃ = 20x + c, for x ∈ [5,9]

To determine c, equate y₂ and y₃ at x = 5

∴ 240 = 20 * 5 + c

∴ c = 240 - 20 * 5 = 240 - 100 = 140

∴ y₃ = 20x + 140, for x ∈ [5,9]

Consequently,

y₁ = 80x, for x ∈ [0,3]

y₂ = 240, for x ∈ [3,5]

y₃ = 20x + 140, for x ∈ [5,9]

The graph plotting the piecewise function that depicts the described situation is shown in the attached illustration.

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1 month ago
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