Two functions are shown in the table below. Function 1 2 3 4 5 6 f(x) = −x2 + 4x + 12 g(x) = −x + 6 Complete the table on your o
wn paper, then select the value that is a solution to f(x) = g(x).
1 answer:
For the function
and
both yield the same result.
Detailed breakdown:
The functions involved are
Step 1:
Insert in
to find the value of
.
Insert in
to find the value of
.
Step 2:
Insert in
to obtain the value of
.
Step 3:
Replace in
to find the value of
.
Step 4:
Insert in
to find the value of
.
Also, replace in
to obtain the value of
.
Step 5:
Insert in
to obtain the value of
.
Replace in
to find the value of
.
Step 6:
Insert into
to find the value of
.
Also, substitute in
to obtain the value of
.
Step 7:
According to the provided condition .
(a). Insert and
into the previously mentioned equation.
(b). Multiply through by on both sides.
(c). Move the term to the left side of the equation.
(d). Divide the middle term so that its sum equals 5 and the product equals 6.
From the analysis above, it is noted that for both functions
and
yield the same outcome.
Using a direct approach:
The table representing function and
is included below.
For more information:
1. What is the y-intercept of the quadratic function f(x) = (x – 6)(x – 2)? (0,–6) (0,12) (–8,0) (2,0)You might be interested in
It is established that
A correlation between two variables, x and y, demonstrates a direct variation if it can be written in the format or
For this question, we have
the point lies on the direct variation line
therefore
Determine the constant of proportionality k
-------> substitute ------>
The equation is
Keep in mind that
If a point is located on the direct variation line
then
the point has to fulfill the direct variation equation
we will now validate each point
case A) point
Insert the values of x and y into the direct variation equation
-------> is valid
thus
the point lies on the direct variation line
case B) point
Insert the values of x and y into the direct variation equation
-------> is valid
thus
the point lies on the direct variation line
case C) point
Insert the values of x and y into the direct variation equation
-------> is not valid
thus
the point does not lie on the direct variation line
case D) point
Insert the values of x and y into the direct variation equation
-------> is valid
thus
the point lies on the direct variation line
case E) point
Insert the values of x and y into the direct variation equation
-------> is not valid
thus
the point does not lie on the direct variation line
case F) point
Insert the values of x and y into the direct variation equation
-------> is valid
thus
the point lies on the direct variation line
ultimately
the solution is
I just took this assessment and got it right; the answer is a term with a degree of 5. It’s option 4.
