If 4A = 3B = 2C, find A : B : C

According to the rule of 72,
72/rate=time
72÷9.6=7.5 years

An alternative method for resolution using the main formula
2300=1150(1+0.096/4)^4t
Isolate t
t=((log(2,300÷1,150)÷log(1+(0.096÷4))÷4))=7.31 years

I hope this is helpful:-)

Answer:  the factored form is (4x+8)(x-9)

Step-by-step explanation:

¡Hola! Bienvenido a!

Vamos a sumar cuántas canicas tenemos en total.

12+11+17+5=45

Queremos hallar la probabilidad de elegir una canica que no sea azul. Observemos cuántas canicas no son azules.

12+11+5=28

Tendremos esta probabilidad sobre 48.

28/48

Al simplificar, obtenemos 7/12 o alrededor de 58.33%.

¡Espero que esto ayude!

Answer:

The distance from the point (0,1,1) to the specified line is zero.

Step-by-step explanation:

Considering the parametric equations of the line,

x=2t, y=5-2t, z=1+t

In order to calculate the distance from (0,1,1), we must remove t from the equations above, such that

whose direction ratios are (l,m,n)=(3,2,-2) and the distance from point (a,b,c)=(0,1,1) is defined as

The distance between the point (0,1,1) and (1) amounts to zero. Therefore, the point (0,1,1) is located on the line (1).

Jack swims a total distance of 9*25.0m=225.0 meters in 2 minutes and 34.5 seconds.

The time duration of 2 minutes and 34.5 seconds can be converted to seconds: 2*60sec +34.5 sec= 154.5 s


Jill completes 10*25.0m = 250 m also in 154.5 s.










Therefore,
the speed of Jack calculates to: 225.0 meters / 154.5 s =(225/154.5) m/s = 1.46 m/s

the speed of Jill calculates to: 250.0 meters / 154.5 s =(250/154.5) m/s = 1.62 m/s


Assuming both Jack and Jill start from point 0 moving in the positive direction,

an even number of lengths results in a Displacement of 0, while an odd number results in a Displacement of 25 m


Thus, Jill's average Velocity is 0,

and Jack's average velocity is 25/154.5 = 0.16 m/s

Answer:

Jack's Average Speed: 1.46 m/s

Jill's Average Speed: 1.62 m/s

Jack's Average Velocity: 0

Jill's Average Velocity: 0.16 m/s