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Ivenika
7 days ago
13

A poster has an area of 432 square inches. The length x in inches is 6 inches longer than the width of the poster. Which can be

solved to determine the length, in inches, of the poster?
A) x^2 -6 =432
B) x^2 -6x =432
C) x^2 + 6 =432
D) x^2 +6x =432
Mathematics
1 answer:
lawyer [12.1K]7 days ago
3 0
La respuesta correcta es D
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Wyjaśnienie krok po kroku:

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Użyj mnożników Lagrange'a, mamy

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Dzieląc otrzymujemy

\frac{y}{x} =\frac{x}{y} \\x^2=y^2

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Stąd wymiary to

(2x,2y,2z)

<pzatem wymiary="" to="">

\frac{2}{\sqrt{3} },\frac{2}{\sqrt{3} },\frac{2}{\sqrt{3} } )

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