Answer:
Confidence limit = [52.8%, 75.2%]
Step-by-step explanation:
± 
where the value will be sourced from the z-table regarding a 95% confidence interval
1-0.95= 0.05/2= 0.025
0.95+0.025= 0.0975
From the z-table, the value of linked to 0.0975 is 1.96
± 
± 
± 
% ± 
%
thus, the confidence interval is
%
%
![[52.8, 75.2]](https://tex.z-dn.net/?f=%5B52.8%2C%2075.2%5D)
There exist two coefficients: one pertains to x raised to the first degree, and another corresponds to the zeroth degree of x (the constant term).
Thus:
the coefficient for the constant term is 42 (i.e. 42x^0=42).
the coefficient for the linear term is 2 (i.e. 2x^1=2x)
<span>0.002 1/10 of what
=> (1/10)a = 0.002
=> Multiply both sides by 10 to solve for the unknown number, since we need the value whose one-tenth is 0.002.
=> 10 x (1/10)a = 10 x 0.002
=> a = 0.02
Therefore, 0.002 is one-tenth of 0.02.
To verify, divide 0.02 by 10.
=> 0.02 / 10
=> 0.002
Hence, the solution is confirmed.
</span>
V = x³ - 6x²y + 12xy² - 8y³
V = (x - 2y)³
= (x - 2y)(x - 2y)(x - 2y) ( start by expanding the first pair of factors )
= (x² - 4xy + 4y²)(x - 2y) ( multiply the terms from the first group with those in the second )
= x³ - 4x²y + 4xy² - 2x²y + 8xy² - 8y³ ( combine similar terms )
= x³ - 6x²y + 12xy² - 8y³
