<span>The likelihood of both selected students being sophomores is 6/20, which simplifies to 3/10.
The expression for the probability that both chosen students are sophomores is (6c1) (5c1) /(20c2)
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The minimum distance is the same from both points because their lengths are equal.
Answer:
A Type II error occurs when the null hypothesis is not rejected, even when the alternative hypothesis is actually valid.
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The implication is that the new method may be dismissed or altered despite it being a real enhancement.
Step-by-step explanation:
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Answer:
Step-by-step breakdown:
The necessary formula for this problem is
which resolves to
leading to
36 + 6x = 40 + 5x, and consequently
x = 4
Thus, DG equals 5 + 4 + 3, resulting in 12
A geometric sequence models the bounce heights:
Use the formula
A (subscript n) = Ar(n-1)
a = the first-term value
n = the index of the term you want (for the fourth peak, n = 4)
r = common ratio, found by dividing the second term by the first
Here r = 18/27 = 2/3 because 27×(2/3) = 18, and similarly 18×(2/3) = 12
For the fourth peak n = 4
Compute: 4th term = 27(2/3)^(4-1) = 8
Therefore the height at the fourth peak is 8
