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3241004551
8 days ago
10

A church has 8 bells in its bell tower. Before each church service 5 bells are rung in sequence. No bell is rung more than once.

How many sequences are​ there?
Mathematics
2 answers:
Inessa [3.9K]8 days ago
8 0
Utilize the! operation to determine the count of combinations.

8!/5! = 40,320/120 = 336
babunello [3.6K]8 days ago
6 0
The total number of sequences is
120.
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The length if Marshall's rectangular poster is 2 times its width.If the perimeter is 24 inches, what is the area of the poster.
Inessa [3907]
Dimensions of the rectangle are defined as Length=2x
Width=x
The formula for perimeter is given by 2(Length) + 2(Width).

First, we need to determine the dimensions of the rectangle, specifically its length and width.

We can derive this equation:
24=2(2x)+2(x)
4x+2x=24
6x=24
x=24/6
x=4

Consequently, Length becomes 2x, leading to 2(4)=8.

Therefore, the length is 8 inches and the width is 4 inches.

Next, we will calculate the area of the rectangle.
The area can be computed as Length multiplied by Width.

Area=(8 in)(4 in)=32 in²

Conclusion: The area of Marshall's rectangular poster is 32 in².

4 0
9 days ago
As a part-time contractor, you want to test a new cement mixture for a project. You need 2 34 wheelbarrows of sand to make 8 whe
zzz [4022]

Answer: He will require 10.07 cubic feet of sand for the wheelbarrows.

Step-by-step explanation:

Given that

the ratio of wheelbarrows filled with sand to those filled with concrete is expressed as

2\dfrac{3}{4}:8\\\\=\dfrac{11}{4}:8\\\\=11:32

The volume of concrete in wheelbarrows is 248 cubic feet.

Then the volume of sand in wheelbarrows can be found as

(\dfrac{11}{32})^3=\dfrac{x}{248}\\\\\dfrac{1331\times 248}{32^3}=x\\\\10.07=x

Therefore, he will require 10.07 cubic feet of sand for the wheelbarrows.

7 0
7 days ago
Read 2 more answers
Lonzell said the function shown in the graph is positive on the interval (−,) and negative on the interval (−,−)open negative 5
Inessa [3907]

Answer:

The segments of the positive graph are located at the coordinates (-5,-4) and (2,5).

In contrast, the negative segment is identified as (-4,2).

Step-by-step explanation:

The positive graph is above the x-axis, while the negative portion lies beneath the y-axis.

Within the interval (-1,5),

The graph appears below the x-axis between (-1,2)

And above it between (2,5).

At this juncture, Lonzell’s assertion is inaccurate.

Within the interval (-5,-1),

The graph again resides below the x-axis in the range (-4,-1)

And above it between (-5,4).

At this point, Lonzell's assessment remains incorrect.

Thus,

The segments of the positive graph are at the coordinates (-5,-4) and (2,5).

Meanwhile, the negative segment is identified at (-4,2).

5 0
7 days ago
All of the students in Ms. Osbourne's class like pizza. Jeff is a student who likes pizza. Therefore, Jeff is a student in Ms. O
Zina [3914]
Hindi ito palaging totoo.


4 0
13 days ago
Read 2 more answers
Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc
Leona [4166]

To address this problem, let's start by formulating the general motion equation along the vertical direction.

This gives us:

h = \frac {1} {2} gt ^ 2 + vo * t + h0

Where,

  • g: gravitational acceleration
  • vo: initial velocity
  • h0: starting height

For the first individual:

h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21

For the second individual:

h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

When both individuals reach the identical altitude, the following holds:

h1 = h2\\

\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50

Rearranging results in:

\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50

\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21

\frac {19} {12} * t = 29

Solving for time:

t = 29 (\frac {12} {19})\\t = 18.31s

Result:

The two window washers reach the same height after 18.31 seconds.

6 0
16 days ago
Read 2 more answers
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