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saw5
1 month ago
12

Find the amount paid for the loan. $2400 at 10.5% for 5 years

Mathematics
1 answer:
Zina [12.3K]1 month ago
6 0
Loan total = $2400.
It carries an interest rate of 10.5%.
This rate is annual and applies for FIVE years.
First, you calculate 10.5% of $2400, which results in $252.
The answer is $732 annually. 
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The total number of degrees, D, in an n-sided polygon is given by the formula D=180(n-2). When Janelle solves for n, she gets n=
AnnZ [12381]
<span>D = 180 * (n -2)
D = 180n -360
180n = D +360
n = (D / 180) + 2

Thus, the answer is "A"
Additionally, we can verify this using a square where the total angles add up to 360
n = (D / 180) +2
n = (360 / 180) +2
number of sides = 4
correct

Source:
http://www.1728.org/polygon.htm[[TAG_15]][[TAG_16]][[TAG_17]][[TAG_18]][[TAG_19]][[TAG_20]] </span>
3 0
1 month ago
Read 2 more answers
Data from 14 cities were combined for a​ 20-year period, and the total 280 ​city-years included a total of 107 homicides. After
zzz [12365]

Answer:

P(0) = 0.6825

P(1) = 0.2607

Step-by-step explanation:

Based on the provided data, there were 107 homicide incidents and a total of 280 city-years recorded.

Let us denote the variable representing homicides per city-year as X.

The mean value of X can be calculated with the following formula:

\begin{array}{c}\\{\rm{Mean}} = \frac{{107}}{{280}}\\\\ = 0.382\\\end{array}

Mean=   107/280 = 0.382

The average number of homicides per city-year \left( {\lambda = \mu } \right)(λ=μ) is 0.382.

a. To find the probability of no homicides occurring:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^0}}}{{0!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {\rm{1}} \right)}}{1}\\\\ = 0.6825\\\end{array}

P(X=0) =  e  −0.382  (0.382)⁰​/1

= (0.6825)(1) /1

P(X=0) = 0.6825

Thus, the chance of experiencing zero homicides P(0) is 0.6825.

b. To determine the probability of one homicide occurring:

\begin{array}{c}\\P\left( {X = 1} \right) = \frac{{{e^{ -0.382}}{{\left( {0.382} \right)}^1}}}{{1!}}\\\\ = \frac{{\left( {0.6825 \right)\left( {0.382} \right)}}{1}\\\\ = 0.2607\\\end{array}

P(X=1) =  e  −0.382  (0.382)¹​/1

= (0.6825)(0.382)/1

P(X=1) = 0.2607

Thus, the probability of having one homicide P(1) is 0.2607.

​

5 0
1 month ago
Choose the solutions of the following systems of equations x^2+y^2=6 and x^2-y=6
AnnZ [12381]

Answer:

The solutions are (-√6,0) and (√6,0)

(-√5,-1) and (√5,-1)

Step-by-step explanation:

We start with the equations:

{x}^{2} + {y}^{2} = 6

and

{x}^{2} - y = 6

Rearranging the second equation to make y the subject results in;

y = {x}^{2} - 6

Substituting into the first equation gives us:

{x}^{2} + ({x}^{2} - 6 )^2= 6

x = \pm \sqrt{6}

and x = \pm \sqrt{5}

The solutions remain as (-√6,0) and (√6,0)

(-√5,-1) and (√5,-1)

7 0
1 month ago
N the diagram below, points $A,$ $E,$ and $F$ lie on the same line. If $ABCDE$ is a regular pentagon, and $\angle EFD=90^\circ$,
Zina [12379]

Answer:

:0000000000000000000000

7 0
1 month ago
A high school theater club has 40 students, of whom 6 are left-handed. Two students from the club will be selected at random, on
babunello [11817]

Response:

1.92\%

Detailed explanation:

Probability for an event is calculated as the ratio of the size of the event space compared to that of the sample space.

The sample space encompasses all possible outcomes.

Event space represents the number of favorable outcomes for the event in question.

Thus

Let

x ------> size of event space

y ----- → size of sample space

so

P=\frac{x}{y}

Calculate the probability of the first student being left-handed

we have

x=6

y=40

substituting values

P=\frac{6}{40}

Simplify

P=\frac{3}{20}

Calculate the probability of the second student being left-handed

we have

x=6-1=5

y=40-1=39

substituting values

P=\frac{5}{39}

Calculate the probability that both selected students will be left-handed

Multiply the probabilities together.

P=\frac{3}{20}(\frac{5}{39})=\frac{15}{780}

Convert to percentage

Multiply by 100

\frac{15}{780}(100)=1.92\%

4 0
1 month ago
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