Norma Jean makes $25 per hour. She works 35 hours per week. She gets a commission of 15% on her total sales. How much should Nor

Step One

Deduct 32 from both sides.

F - 32 = \frac{9}{5}(k - 273.15)

Step Two

Multiply each side by \frac{5}{9}.

\frac{5}{9}(F - 32) = \frac{5}{9} \times \frac{9}{5}(k - 273.15)

\frac{5}{9}(F - 32) = k - 273.15

Step Three

Add 273.15 to both sides.

\frac{5}{9}(F - 32) + 273.15 = k

Problem B

F = 180

Solve for k

k = \frac{5}{9}(F - 32) + 273.15

k = \frac{5}{9}(180 - 32) + 273.15

k = \frac{5}{9} \times 148 + 273.15

k = 82.2222 + 273.15

k = 355.3722

k = 355.4  <<< Answer

Answer:

The illustration provided shows the graph

Step-by-step explanation:

Let

x ------> number of times Emma cuts the grass

y ------> hours Emma spends babysitting

it is known that

------> represents the inequality of the scenario

The solution is the shaded region above the solid line where both x and y are positive

The equation for the solid line is represented as

The slope of the line is negative

The y-intercept is at the point (the y-value when x is zero)

The x-intercept is at (the x-value when y equals zero)

therefore

The illustration provided shows the graph

Response:

The probability that a student has a pet, given they do not have any siblings is:

Option: D ( 60%)

Step-by-step breakdown:

Let A represent the situation where a student lacks a sibling.

Let B signify the occurrence that a student has a pet.

Consequently, A∩B refers to the event in which a student is without siblings but possesses a pet.

Let P denote the chance of an event happening.

We need to determine:

P(B|A)

From our knowledge:

From the data provided:

P(A)=0.25

and P(A∩B)=0.15

Thus,

which expressed as a percentage is:

Therefore, the probability is:

60%