A group of college students built a self-guided rover and tested it on a plane surface. They programmed the vehicle to move alon

Answer:

Step-by-step explanation:

First, we apply the Pythagorean theorem to determine the distance from Manuel’s home to the resort.

S1 = √50²+20²

S1 = √2500+400

S1 = √2900

S1 = 53.85m

Next, we find the distance from Manuel's home to his friend’s residence.

S2 = √15²+10²

S2 = √225+100

S2 = √325

S2 = 18.03m

The distance between the two boys and the resort will be represented as ∆S = S2 - S1.

∆S = 53.84 - 18.03

∆S = 35.81m

Malcolm's remaining distance is roughly
   1370 - 470 - 430 = 470

This coincides with selection...
   D) 470 miles

a=1/100pt is the right solution. Initially, you need to multiply both sides of the equation by t, which results in ⇒ . After that, inverting the equation gives ⇒. Alternatively, dividing both sides of the equation by one hundred (100) also leads us to . Ultimately, the final answer is a=1/100pt is the result. I hope this offers assistance! Thank you for asking your question, and enjoy your day. -Charlie

Answer:

Please refer to the explanation

Step-by-step explanation:

Given that:

Sarah, Jose, and you all reside on the same street:

The distance between you and Jose is 5 blocks

The distance between Jose and Sarah is 2 blocks

Calculating the distance (b) between you and Sarah:

Since it is not specified if Sarah is closer to you or to Jose;

Thus;

Distance b from you to Sarah will be:

(The distance to Jose ± the distance to Sarah)

b = (5 ± 2)

b = (5 + 2) or (5 - 2)

b = 7 blocks or 3 blocks

The test statistic (Z) is 2.5767, and the p-value of the test is 0.009975. The null hypothesis suggests that the smoking rate among students has not changed, while the alternative indicates otherwise. The z-statistic for the sampled proportion is computed, yielding z ≈ 2.5767. As we investigate whether the smoking percentage has shifted over the preceding five years, the two-tailed p-value is found to be 0.009975. This result is significant at a 99% confidence level, demonstrating substantial evidence that the percentage of smoking students has changed.