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zysi
2 months ago
10

Suppose that a scheduling algorithm (at the level of short-term CPU scheduling) favors those processes that have used the least

processor time in the recent past. Why will this algorithm favor I/O-bound programs and yet not permanently starve CPU-bound programs?
Computers and Technology
1 answer:
Harlamova29_29 [1K]2 months ago
8 0

Answer:

The response to the question is:

I/O-bound

programs do not heavily rely on CPU time, typically experiencing brief CPU bursts.

In contrast, CPU-bound programs need extensive CPU bursts. Starvation is not a concern for CPU-bound processes since I/O-bound programs conclude their execution more rapidly, frequently allowing CPU-bound programs access to the CPU.

Explanation:

I/O-bound threads usually experience tight latencies, which must be compared against computer-bound threads during Windows tasks.

For instance, a mouse click elicits a quick response, unlike a batch job that operates in the background.

If the process is slower, a user may change operating systems, and server workloads tend to disregard UI responsiveness.

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2 months ago
Write the definition of a function printAttitude, which has an int parameter and returns nothing. The function prints a message
Natasha_Volkova [1026]

Answer:

The C++ function definition for printAttitude can be seen below.

void printAttitude(int n)

{

switch(n)

{

case 1: cout<<"disagree"<<endl; break;

case 2: cout<<"no opinion"<<endl; break;

case 3: cout<<"agree"<<endl; break;

default: break;

}

}

Explanation:

It is notable that this method takes an int parameter.

Since it yields no value, it has a void return type.

The console displays messages based on the integer parameter, n, using a switch statement.

Output conditions are specified in different cases.

The default case takes care of values where no output is needed.

Each case concludes with a break statement to end the execution of the program.

This function can be utilized within a program as illustrated.

PROGRAM

#include <iostream>

using namespace std;

void printAttitude(int n)

{

switch(n)

{

case 1: cout<<"disagree"<<endl; break;

case 2: cout<<"no opinion"<<endl; break;

case 3: cout<<"agree"<<endl; break;

default: break;

}

}

int main() {

// variables to hold respective value

int n;

// user input taken for n

cout<<"Enter any number: ";

cin>>n;

// calling the function taking integer parameter

printAttitude(n);

return 0;

}

OUTPUT

Enter any number: 11

1. The user input is taken for the integer parameter.

2. Inside main(), the method, printAttitude(), is called with the user-input as a parameter.

3. If a user enters 11, which does not match any of the case values, the default case is executed, which does nothing and the break statement runs.

4. Thus, nothing is displayed for the input of 11.

5. When the user inputs 3, the corresponding case block is executed since it matches the case values.

6. The program produces the following output when the user inputs 3.

OUTPUT

Enter any number: 3

agree

The program concludes with a return statement.

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1 month ago
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