Suppose that we have a set of activities to schedule among a large number of lecture halls, where any activity can take place in

Respuesta: Te proporcioné 6 opciones de las cuales puedes elegir.

Integridad

Escalabilidad

Calidad de Servicio

Tolerancia a Fallos

Redes de Línea Eléctrica

Seguridad

Response:

#include <iostream>

using namespace std;

int main()

{

   string Fname, Lname;

   cout << "Please enter your first name " <<"Please enter your last name" <<endl;

   cin>>Fname>>Lname;

   cout<<Lname<<", "<<Fname<<endl;

   return 0;

}

Clarification:

This code is coded in the C++ programming language. To begin with, two string variables are declared, namely Fname and Lname for the first and last names, respectively. The C++ cout function is utilized to ask users for their inputs, while the cin function takes in user inputs and stores them in the corresponding variables. The cout operator (<<) arranges the output in accordance with the specification given in the question

Response:

s

Clarification:

x

The answer is B.

Answer:

a) Transforming each character into its binary equivalent:

73:

The digits are 7 and 3

7 in binary is: 111

3 in binary is: 11

Thus

73: 0_111_0011

Likewise

F4:

F stands for 15 and its binary is: 1111

4 in binary: 100

Consequently

F4:  1_111_0100

E5:

E corresponds to 14 and its binary form is: 1110

5 in binary: 101

Therefore

E5:  1_110_0101

76:

7 in binary: 111

6 in binary: 110

Hence

76:  0_111_0110

E5:

E has a binary representation of: 1110

5 in binary: 101

Consequently

E5:  1_110_0101

4A:

4 in binary: 100

A represents 10

A in binary form: 1010

Therefore

4A:  0_100_1010

EF:

E in binary is: 1110

F in binary is: 1111

Thus

EF: 1_110_1111

62:

6 in binary form: 110

2 in binary form: 10

Therefore

62:  0_110_0010

73:

The digits are 7 and 3

7 in binary is: 111

3 in binary is: 11

Thus

73: 0_111_0011

for 0_1110011: the decimal equivalent is: 115 which translates to s

for 1_1110100:  the decimal equivalent is: 116 which translates to t

for 1_1100101:  the decimal equivalent is: 101 which translates to e

for 0_1110110: the decimal equivalent is:  118 which translates to v

for 1_1100101:  the decimal equivalent is: 101 which translates to e

for 0_1001010: the decimal equivalent is:  74 which translates to j

for 1_1101111: the decimal equivalent is: 111 which translates to o

for 0_1100010:  the decimal equivalent is: 98 which translates to b

for 0_1110011: the decimal equivalent is:  115 which translates to s

Thus the decoded sequence is:  stevejobs

b) The parity being utilized is odd.

for 0_1110011:  There are 5 instances of 1s and the parity is 0 indicating it is odd.

for 1_1110100: There are 4 instances of 1s and the parity is 1 indicating it is odd.

Thus, we count the number of 1s and then verify if the parity is odd or even.

Likewise

for 1_1100101:  the parity is odd

for 0_1110110: the parity is odd

for 1_1100101:  the parity is odd

for 0_1001010: the parity is odd

for 1_1101111: the parity is odd

for 0_1100010: the parity is odd

for 0_1110011: the parity is odd

Therefore, the parity being used is odd.