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laila
2 months ago
14

23 POINTS Noah and Gabriel are in the same English class. They have taken 6 quizzes so far. Find the measures of center for each

of the students. Noah’s scores: 84, 85, 85, 86, 90, 92 Total of 522 Gabriel’s scores: 82, 85, 86, 86, 90, 94 Total of 523 What are Noah’s mean, median, and mode? What are Gabriel’s mean, median, and mode?
Mathematics
2 answers:
babunello [11.8K]2 months ago
6 1

Answer:

noah: median-85.5 mode-85 mean-87

gabriel: median-86 mode-86 mean-87

Step-by-step explanation:

Leona [12.6K]2 months ago
5 0

Answer:

Noah’s average: 87

Noah’s median: 85.5

Noah’s mode: 85

Gabriel’s average: 87.17

Gabriel’s median: 86

Gabriel’s mode: 86

Step-by-step explanation:

The mean is calculated as (total/number of items), or the average.

The median refers to the central value in a dataset.

The mode represents the number that appears most frequently.

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A follow-up study will be conducted with a sample of 20 people from the 300 people who responded yes (support) and no (do not su
PIT_PIT [12445]

Response:

Detailed explanation:

Hello!

Stratified sampling involves the categorization of the population into subgroups based on pre-established criteria for the study. These subgroups consist of homogeneous units concerning the relevant characteristics. In this instance, individuals in the groups will represent only one of the two potential opinions (support or not support) and not both.

The researcher determines the sample size desired, considering several factors such as finances, material availability, and accessibility to experimental subjects (for instance, if they are endangered species, larger sample sizes may not be feasible).

One might conduct proportionate stratified sampling by selecting a proportion of respondents who answered "yes" along with those who answered "no."

In this sampling method, taking a specific proportion from each subgroup allows for a more straightforward extrapolation of results to the overall populations. For example, if you needed a sample size of n = 20, each stratum would ideally contain half, meaning 10 from the “yes” group and 10 from the “no” group.

I hope this is helpful!

4 0
3 months ago
Shane and Abha earned a team badge that required their team to collect no less than 20002000 cans for recycling. Abha collected
tester [12383]

Shane and Abha received a team badge for gathering at least 2000 cans for recycling.

This indicates that their collection must total a minimum of 2000 cans.

Abha managed to collect 178 more cans than Shane.

Let’s denote the number of cans Shane collected as S

So, Abha collected = S + 178

The inequality representing the number of cans collected by Shane can be expressed as:

S+S+178\geq 2000

= 2S+178\geq 2000

2S\geq 2000-178

2S\geq 1822

S\geq 911

3 0
2 months ago
Grant is a member of a book club. He pays a $10 yearly membership fee and can purchase books through the club for $2.75 each. Hi
Svet_ta [12734]
A) The independent variable in this scenario is the quantity of books purchased. C) The overall cost for the year hinges on the number of books obtained. E) The output of this function is the total yearly cost.
5 0
2 months ago
NEED HELP ON NUMBER 13 AND 14
AnnZ [12381]

Answer:

Question 13: For age groups y=1 and y=1.3, the response time is 8 microseconds.

Question 14: The club experienced losses between 11.28 and 4.88 years.

Step-by-step explanation:

Question 13:

The equation that gives the response rate R of 8 microseconds can be expressed as

8=y^4 +2y^3 - 4y^2 -5y +14.

Upon graphing this, we determine the solutions to be

y=1;   y=1.302;     y=-2;    y=-2.302.

We consider only positive values of y applicable in real-life scenarios.

Thus, the response is 8 microseconds solely for the age groups y=1 and y=1.3.

Question 14:

The football club incurs losses when p(t)

Or

t^3 -14t^2 +20t +120

Graphing this inequality reveals the solutions to be

t and 4.88

As only positive values for t are relevant in practical situations, we accept the second solution.

Hence, the club faced losses during the years 4.88

5 0
2 months ago
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