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Sergio039
22 days ago
9

A family purchases a car for $11,000 which depreciates about 16% annually. How much is the car worth after 4 years

Mathematics
2 answers:
Svet_ta [9.5K]22 days ago
8 0

Answer:

$ 5476.58 (approx)

Step-by-step explanation:

In summary,

The car's original price is P = $ 11,000,

Rate of depreciation is r = -16% = -0.16,

Time period is t = 4 years,

Consequently, the car's value will be calculated as follows:

A=P(1-r)^t=11000(1-0.16)^4

=11000(0.84)^4

=\$ 5476.58496

\approx \$ 5476.58

PIT_PIT [9.1K]22 days ago
7 0

11,000 multiplied by 16% equals $1,750, which when multiplied by 4 gives a total of $7,040.

Therefore, after 4 years, the car's value is $11,000 - 7,040 = $3,960.

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Try this method:
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Add 0.0025 kg, 1750 mg, 2.25 g, and 825,000 μg, and express the answer in grams.
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Answer:

6.75g

Step-by-step explanation:

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In a rule of three calculation, the first step is identifying the measures and how they interrelate; whether their connection is direct or inverse.

In direct relationships, as one measure increases, so does the other.

In inverse relationships, as one measure increases, the other decreases.

Problems involving unit conversion, like this, illustrate a direct relationship between measures.

First step: convert 0.0025kg to grams

One kilogram equals 1000 grams, so:

1kg - 1000g

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x = 1000*0.0025 = 2.5g

Thus, 0.0025kg is equal to 2.5g

Second step: handle 1750 mg

One gram consists of 1000mg, so:

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x = 1.75g

Therefore, 1750 mg converts to 1.75g

2.25g is fine

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1 month ago
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Answer:

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La ecuación cuadrática que tenemos es (4y - 3)² = 72

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Question 2

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