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Elan Coil
2 months ago
7

Tristan has found a good job as a bookkeeping clerk after finishing his associates degree at the local community college. He is

making a beginning annual salary of $19,760. How can this increased income affect his financial decisions? Compare his previous budget when he worked part time while finishing his degree with his current budget after getting a full time job.
Monthly budget | Previous Budget | Current Budget

income
Wages | $786 | $1646

Expenses
Rent | $300 | $600
Utilities | $60 | $120
Groceries | $130 | $200
Savings | $120 | $350
Car Expenses | $150 | $150
Entertainment | $20 | $120

Net Income | $6 | $106

a.Tristan is spending too much money on groceries and entertainment.

b.Tristan is earning quite a bit more in his full time job. He is spending more on rent, utilities, food, and entertainment, as well as saving $350 each month.

c.Tristan is earning double his previous wages. He should double his expenses, as well.

d.Tristan's increased income should have no effect on his financial decisions.
Mathematics
2 answers:
Zina [12.3K]2 months ago
8 0

Tristan's higher income is leading to changes in his financial choices since he is now both spending and saving more.

The correct choice is option B.

Tristan is earning significantly more from his full-time position. His expenses have increased for rent, utilities, food, and entertainment, along with saving $350 per month.

tester [12.3K]2 months ago
5 0

B. Tristan is earning substantially more from his full-time job.

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Answer:

V(x)=(4x^{3}-40x^{2}+100x)\ cm^3

The variable x lies within the interval of all positive real numbers less than 5 cm.

Detailed solution:

Problem statement:

Determine the volume of the open-topped box as a function of the side length x (in centimeters) of the square cutouts.

Refer to the provided diagram for clarity.

Define:

x → length in centimeters of each square cutout side

The volume of the box with open top can be written as:

V=LWH

Given this, we have:

L=(10-2x)\ cm

W=(10-2x)\ cm

H=x)\ cm

By substitution:

V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3

Determine the domain of x:

Because:

(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm

Therefore:

Domain is the interval (0,5)

That means all real numbers strictly greater than zero and less than 5 cm are valid for x.

Hence, the volume V as a function of x is:

V(x)=(4x^{3}-40x^{2}+100x)\ cm^3

5 0
3 months ago
A random sample of size n1 = 16 is selected from a normal population with a mean of 75 and standard deviation of 8. A second ran
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4 0
1 month ago
Axline Computers manufactures personal computers at two plants, one in Texas and the other in Hawaii. The Texas plant has 40 emp
Zina [12379]

Answer:

a) The likelihood that none of the sampled employees are from the Hawaii plant is 1.74%.

b) The chance that exactly 1 employee from the sample is found working in the Hawaii plant is 8.70%.

c) There is an 89.56% chance that 2 or more employees in the sample are from the Hawaii plant.

d) The probability that 9 employees from the sample are working at the Texas plant is 8.70%.

Step-by-step explanation:

Each employee has two potential employment locations: either Texas or Hawaii. Thus, the binomial probability distribution can be utilized to solve this scenario.

Binomial probability distribution

This distribution defines the probability of achieving exactly x successes in n trials where there are only two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

Here, C_{n,x} denotes the number of ways to choose x objects from a set of n, represented by the subsequent formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of success occurring.

In this context, we know:

The sample comprises 10 employees, therefore n = 10.

a. Calculate the probability that none of the sampled employees are from the Hawaii plant (to 4 decimals)?

Given that 20 out of 60 employees are based in Hawaii:

p = \frac{20}{60} = 0.333

We aim to find P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.333)^{0}.(0.667)^{10} = 0.0174

Thus, the likelihood that none in the sample are from Hawaii stands at 1.74%.

b. Calculate the probability that 1 employee from the sample is from the Hawaii plant?

This is represented as P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{10,1}.(0.333)^{1}.(0.667)^{9} = 0.0870

Therefore, there is an 8.70% possibility that 1 employee in the sample comes from Hawaii.

c. Calculate the probability that 2 or more employees in the sample are from the Hawaii plant?

We can observe two scenarios: either fewer than 2 employees are from Hawaii or 2 and beyond. The combined probabilities equal decimal 1. So:

P(X < 2) + P(X \geq 2) = 1

We seek to find P(X \geq 2).

P(X \geq 2) = 1 - P(X < 2)

From problems a and b, we possess values for both probabilities.

P(X < 2) = P(X = 0) + P(X = 1) = 0.0174 + 0.0870 = 0.1044

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1044 = 0.8956

Accordingly, the chance that 2 or more employees in this sample operate at the Hawaii plant is 89.56%.

d. Calculate the likelihood that 9 employees in the sample are working at the Texas plant?

This corresponds to the probability found in part b for 1 employee working in Hawaii.

Consequently, there is an 8.70% chance that 9 employees belong to the Texas plant.

6 0
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