The answer is 10. Between 10 and 35, there are 7 prime numbers: 11, 13, 17, 19, 23, 29, and 31. Multiplying 11 by any of the others yields a product smaller than 350, resulting in 6 products. The product of 13 with anything below 26 will also be less than 350, adding 3 more products. Similarly, the product of 17 with anything below 20 yields 1 additional product. Therefore, the total count of different products under 350 amounts to 10.
Step One
Deduct 32 from both sides.
F - 32 = \frac{9}{5}(k - 273.15)
Step Two
Multiply each side by \frac{5}{9}.
\frac{5}{9}(F - 32) = \frac{5}{9} \times \frac{9}{5}(k - 273.15)
\frac{5}{9}(F - 32) = k - 273.15
Step Three
Add 273.15 to both sides.
\frac{5}{9}(F - 32) + 273.15 = k
Problem B
F = 180
Solve for k
k = \frac{5}{9}(F - 32) + 273.15
k = \frac{5}{9}(180 - 32) + 273.15
k = \frac{5}{9} \times 148 + 273.15
k = 82.2222 + 273.15
k = 355.3722
k = 355.4 <<< Answer
Answer:
0.03
Step-by-step explanation:
Yes, we all appreciate the copy and paste from Khan Academy
Response:
The equation of the linear function can be represented as:
H(S) = 960 - 3.2*S
