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2 months ago

What web 2.0 features allows users to subscribe to a data plan that charges for the amount of time spent on the internet?

Computers and Technology

1 answer:

Rzqust [1K]2 months ago

3 0

Answer:

The solution to this inquiry can be found in the explanation provided. The right choice is long tail.

Explanation:

a.Folksonomy

Folksonomy involves organizing online data and content collaboratively. With Web 2.0, individuals can work together to tag and manage various media like photos and journals. As participation grows, a classification system emerges for this content, making this option incorrect.

b. long tail (correct option)

Some platforms allow users to subscribe on a monthly basis or pay periodically, similar to Netflix.

c.user participation

All users have the liberty to contribute to the platform, making many Web 2.0 sites publicly accessible. For instance, Wikipedia allows anyone to edit articles, enabling information to flow both ways instead of being solely provider-driven.

d.application

Web 2.0 applications permit anyone to create and disseminate content or information they have produced. Part of this includes various types of applications like wikis, blogs, social networks, folksonomies, podcasting, and content hosting services.

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2 months ago

Write the state of the elements of each of the following arrays after each pass of the outermost loop of the selection sort algo

Natasha_Volkova [1026]

Answer:

Below is the explanation provided.

Elaboration:

In the first array => 8, 5, -9, 14, 0, -1, -7, 3.

8, 5, -9, 14, 0, -1, -7, 3 For the first iteration, find the smallest from the first to the eighth and reposition the third element in the first place.
-9, 8, 5, 14, 0, -1, -7, 3 In the second round, identify the smallest from the second to eighth and adjust the penultimate element in the second slot.
-9, -7, 8, 5, 14, 0, -1, 3 For the third pass, find the least from third to eighth and move the second last item from that segment.
-9, -7, -1, 8, 5, 14, 0, 3 For the fourth pass, find the minimum from the fourth to eighth and shift the last second item from that section.
-9, -7, -1, 0, 8, 5, 14, 3 For the fifth pass, seek for the smallest from the fifth to eighth and place the last element from that portion.
-9, -7, -1, 0, 3, 8, 5, 14 For the sixth pass, identify the smallest from the sixth to eighth and shift the last second element from that group.
-9, -7, -1, 0, 3, 5, 8, 14 are in order now.

In the second array => 15, 56, 24, 5, 39, -4, 27, 10.

15, 56, 24, 5, 39, -4, 27, 10 In the first iteration, identify the smallest item from the first to the eighth and reposition the last third item in that section.
-4, 15, 56, 24, 5, 39, 27, 10 In the second round, find the minimum item from second to eighth and interchange the last fourth item in that segment.

-4, 5, 15, 56, 24, 39, 27, 10 For the third pass, select the smallest from the third to eighth and shift the last item from that set.
-4, 5, 10, 15, 56, 24, 39, 27 For the fourth stage, determine the smallest from the fourth to eighth and do not shift its position as it is already sorted.
-4, 5, 10, 15, 56, 24, 39, 27 For the fifth iteration, check for the smallest from the fifth to the eighth and intersperse the last third item from that section.

-4, 5, 10, 15, 24, 56, 39, 27 For the sixth phase, find the smallest from the sixth to the eighth and exchange the last item in the sixth.

-4, 5, 10, 15, 24, 27, 56, 39 are in order now.

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