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3 months ago

A sports car can move 100.0 m in the first 4.5 s of constant acceleration.

Physics

2 answers:

Yuliya22 [3.3K]3 months ago

6 0

The acceleration of the car is 22.2 recurring meters per second squared

kicyunya [3.2K]3 months ago

4 0

Answer:

The car's acceleration is represented as $a=9.87\ m/s^2$

Explanation:

The initial speed of the car is u = 0

The distance the car travels is d = 100 m

Time elapsed, t = 4.5 s

Let a represent the car's acceleration, which can be found using the second equation of kinematics:

$d=ut+\dfrac{1}{2}at^2$

$d=\dfrac{1}{2}at^2$

$a=\dfrac{2d}{t^2}$

$a=\dfrac{2\times 100}{(4.5)^2}$

$a=9.87\ m/s^2$

Consequently, the car's acceleration is $9.87\ m/s^2$ . Thus, this provides the sought answer.

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Answer:

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Explanation:

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Using the distance formula

$d =vt$

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