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goblinko
19 days ago
13

A sports car can move 100.0 m in the first 4.5 s of constant acceleration.

Physics
2 answers:
Yuliya22 [2.4K]19 days ago
6 0
The acceleration of the car is 22.2 recurring meters per second squared

kicyunya [2.2K]19 days ago
4 0

Answer:

The car's acceleration is represented as a=9.87\ m/s^2

Explanation:

The initial speed of the car is u = 0

The distance the car travels is d = 100 m

Time elapsed, t = 4.5 s

Let a represent the car's acceleration, which can be found using the second equation of kinematics:

d=ut+\dfrac{1}{2}at^2

d=\dfrac{1}{2}at^2

a=\dfrac{2d}{t^2}

a=\dfrac{2\times 100}{(4.5)^2}

a=9.87\ m/s^2

Consequently, the car's acceleration is 9.87\ m/s^2. Thus, this provides the sought answer.

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Answer:

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Explanation:

The calculation for the electric field is illustrated below:

E = k*|q|/r²

Where:

E = electric field; k = 8.98755*10⁹ N*m²/C²; r = distance separating the field being measured from the point charge = 0.05 m; q = point charge

For a length of 0.100 m of the axon, the value of q is calculated as:

q = (5.6*10¹¹)*(+e)*(0.001)

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q = (5.6*10¹¹)*(1.60217*10^-19)*(0.0001) = 8.972*10^-12 C

Consequently:

E = (8.98755*10⁹)*(8.972*10^-12)/0.05² = 32.255 N/C

A positive point charge produces an electric field that radiates outward, while a negative point charge creates an electric field directed inward.

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