answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
statuscvo
18 days ago
13

Russ makes the diagram below to organize his notes about how Newton’s first law describes objects at equilibrium.

Physics
2 answers:
Ostrovityanka [2.2K]18 days ago
8 0

Correct options:

There is no net force acting on it.

Explanation:

According to Newton's first law, referred to as the law of inertia:

"An object that remains stationary when there is no net force will stay in that state, and an object moving uniformly when there is no net force will continue to move uniformly"

The first scenario (object at stationary) is termed static equilibrium, while the second scenario (object moving uniformly) is termed dynamic equilibrium. As deduced from the description of Newton's first law, both scenarios reflect an object under the influence of a net force of zero, indicating this label belongs in section X (the area shared by both dynamic and static equilibrium).

kicyunya [2.2K]18 days ago
6 0
According to Newton's first law, an object remains at rest until an external force acts upon it, or an object in motion continues to move at a constant speed without accelerating.

Thus, x can solely represent a body coming to a halt. Accordingly, the last option is the most correct.
You might be interested in
Two trains are headed towards each other on the same track unbeknownst to the engineers. One departs San Francisco. Its average
ValentinkaMS [2425]

Answer:

7.166 hours = 430 minutes.

Explanation:

As both trains are approaching each other on the same track, their relative speed is the sum of their individual speeds. Hence, the time until they intersect (and inevitably collide) is determined by how long it takes for speeds of 65 mph and 55 mph to cover the total distance of 860 miles. One train will cover part of the distance, while the other will cover the remainder. To calculate the required time, we can apply the formula:

1 hour ---> 120 miles

X ----> 860 miles; hence X = (860 miles * 1 hour)/120 miles = 43/6 hours = 7.16666 hours. To convert this into minutes, recall that 1 hour equals 60 minutes; therefore, 43/6 hours * 60 minutes/hour = 430 minutes.

7 0
22 days ago
To study torque experimentally, you apply a force to a beam. One end of the beam is attached to a pivot that allows the beam to
kicyunya [2264]

Answer:

a)  τ = i ^ (y F_{z} - z F_{y}) + j ^ (z Fₓ - x F_{z}) + k ^ (x F_{y} - y Fₓ)

b) τ = (-0.189i ^ -5.6 j ^ + 33.978k ^) N m

c) α = (-7.8 10⁻⁴ i ^ - 2.3 10⁻² j ^ + 1.4 10⁻¹ k ^) rad / s²

Explanation:

a) The torque can be expressed as

        τ = r x F

To tackle this equation, using the determinant approach is the most straightforward method

        \tau =\left[\begin{array}{ccc}i&j&k\\x&y&z\\F_{x}&F_{y} &F_{z}\end{array}\right]  

The resulting expression is

      τ = i ^ (y F_{z} - z F_{y}) + j ^ (z Fₓ - x F_{z}) + k ^ (x F_{y} - y Fₓ)

b) Now let's compute

     τ = i ^ (0.075 1.4 -0.035 8.4) + j ^ (0.035 2.8 - 4.07 1.4) + k ^ (4.07 8.4 - 0.075 2.8)

     τ = i ^ (- 0.189) + j ^ (-5.6) + k ^ (33,978)

     τ = (-0.189i ^ -5.6 j ^ + 33.978k ^) N m

c) To find angular acceleration, we use

       τ = I α

       α = τ / I

The moment of inertia being a scalar means that only the magnitude of each component changes, orientation remains constant.

           

     α = (-0.189i^  -5.6 j^  + 33.978k^) / 241

     α = (-7.8 10⁻⁴ i ^ - 2.3 10⁻² j ^ + 1.4 10⁻¹ k ^) rad / s²

8 0
6 days ago
The image illustrates that as the distance between two objects increases, the force of gravity ____________. A) decreases. B) in
Sav [2230]
The image is absent (but it's not essential to resolve the issue).

The right response is A) decreases, as gravitational force is inversely related to the square of the distance. The magnitude of the gravitational force between two masses M and m, separated by a distance d, is expressed as
F=G \frac{Mm}{d^2}
where G is the gravitational constant. The formula demonstrates that as the distance d between the two masses increases, the force magnitude diminishes.
7 0
12 days ago
Read 2 more answers
A composite wall separates combustion gases at 2400°C from a liquid coolant at 100°C, with gas and liquid-side convection coeffi
Ostrovityanka [2208]

Response:

\text{heat loss} = 24864.05 \ W/m^2

Clarification:

If

  • T_1, T_2 represent the temperatures of gases and liquids in Kelvins,
  • t_1 and t_2 denote the thicknesses of the gas layer and steel slab in meters,
  • h_1, h_2 are the convection coefficients for gas and liquid in W/m^2 \cdot K,
  • R_c represents the contact resistance in m^2 \cdot K/W,
  • and k_1, k_2 signify thermal conductivities of gas and steel in W/m \cdot K,

then: part(a):

\text{heat loss } = \frac{T_1 - T_2} { \frac{1}{h_1} + \frac{t_1}{t_2} + R_c + \frac{t_2}{k_2} + \frac{1}{h_2}}

by employing known values:

\text {heat loss} = 2486.05 W/m^2

part(b): Utilizing the rate equation:

\text {heat loss} = h_1 (T_1 - T_{s1})

the surface temperature is T_{s1} = 1678.438 \ K

and T_{c1} = T_{s1} - \frac {t_1 (\text{heat loss})}{k_1} = 1664.560 \ K

Correspondingly

T_{c2} = T_{c1} - R_c (\text{heat loss}) = 421.357 \ K

T_{s2} = T_{c2} - \frac {t_2 (\text{heat loss})}{ k_2} = 397.864 \ K

The temperature profile is depicted in the image provided

3 0
14 days ago
A specimen of steel has a rectangular cross section 20 mm wide and 40 mm thick, an elastic modulus of 207 GPa, and a Poisson’s r
Softa [2035]

Response: The width decreases by 2.18 × 10^(-6) m

Clarification:

Given data;

Shear Modulus; E = 207 GPa = 207 × 10^(9) N/m²

Force; F = 60000 N.

Poisson’s ratio; υ = 0.30

The initial width is 20 mm, and the thickness is 40 mm.

Area = 20 × 10^(-3) × 40 × 10^(-3)

Area = 8 × 10^(-4) m²

The formula for shear modulus is;

E = σ/ε_z

where σ represents stress calculated as Force(F)/Area(A)

while ε_z stands for longitudinal strain.

Thus;

E = (F/A)/ε_z

ε_z = (F/A)/E

ε_z = (60,000/(8 × 10^(-4)))/(207 × 10^(9))

ε_z = 3.62 × 10^(-4)

Next, the lateral strain is given by;

ε_x = - υ × ε_z

ε_x = -0.3 × 3.62 × 10^(-4)

ε_x = -1.09 × 10^(-4)

The change in width can be determined as;

Δw = w_o × ε_x

Where w_o denotes the original width = 20 × 10^(-3) m

So; Δw = 20 × 10^(-3) × -1.09 × 10^(-4)

Δw = -2.18 × 10^(-6) m

A negative sign indicates a reduction in width.

Therefore, the width decreases by 2.18 × 10^(-6) m

6 0
17 days ago
Other questions:
  • 2) Billy jumps upward with a velocity of 4.2 m/s off a 6m high diving board. What is his final velocity once he hits the water?
    15·1 answer
  • A 1100kg car pulls a boat on a trailer. (a) what total force resists the motion of the car, boat,and trailer, if the car exerts
    12·1 answer
  • A very long uniform line of charge has charge per unit length λ1 = 4.80 μC/m and lies along the x-axis. A second long uniform li
    14·1 answer
  • Imagine you are a water molecule, carbon atom, or nitrogen atom that is inside a cow. Write a brief explanation of how you got f
    7·1 answer
  • A sports car can move 100.0 m in the first 4.5 s of constant acceleration.
    13·2 answers
  • If the potential difference across the bulb in a certain flashlight is 3.0 V, What is the potential difference across the combin
    7·1 answer
  • When you urinate, you increase pressure in your bladder to produce the flow. For an elephant, gravity does the work. An elephant
    12·1 answer
  • Ellen does an experiment by releasing a ball from a height of 1 m above each floor in a tall building. She records the time it t
    8·2 answers
  • A hiker walks 9.4 miles at an angle of 60° south of west. Find the west and south components of the walk. Round your answers to
    14·2 answers
  • Assume that charge −q is placed on the top plate, and +q is placed on the bottom plate. What is the magnitude of the electric fi
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!