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Travka
21 day ago
12

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

s in the Caribbean. A Caribbean vacation resort recently advertised in Bride Magazine that the cost of a Caribbean wedding was less than $30,000. Listed below is a total cost in $000 for a sample of 8 Caribbean weddings. At the 0.05 significance level, is it reasonable to conclude the mean wedding cost is less than $30,000 as advertised? 29.128.528.829.429.829.830.130.6
Mathematics
1 answer:
zzz [9K]21 day ago
8 0

Answer:

Based on the findings, we infer that the average cost of a wedding is lower than the $30,000 that was initially suggested.

Step-by-step explanation:

The following data set is provided: (in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}

where x_i denotes data points, \bar{x} represents the mean, and n indicates the number of samples.

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{236100}{8} = 29512.5

The sum of squares of the differences equals 3408750

S.D = \sqrt{\frac{3408750}{7}} = 697.82

The population mean, μ = $30,000

The sample mean, \bar{x} = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $697.82

Initially, we formulate the null hypothesis and the alternative hypothesis.

H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars} A one-tailed t-test will be conducted for this analysis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

<pinserting the="" values="" we="" derive="">

t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975

<pnow>

t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894

<pgiven the="" situation="">

t_{stat} < t_{critical}

<pwe do="" not="" accept="" the="" null="" hypothesis="" and="" reject="" it.="">

Thus, we conclude that the average wedding cost is indeed less than the advertised $30,000.

</pwe></pgiven></pnow></pinserting>
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