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Vadim26
2 months ago
5

Caleb invested $8700 in a savings account with a yearly interest rate of 3% for 7 years. How much simple interest did he earn?

Mathematics
2 answers:
Inessa [12.5K]2 months ago
7 0

The answer is:

letter b

Step-by-step explanation:

Inessa [12.5K]2 months ago
4 0
Simple interest calculation
i = prt
where i represents the interest earned, p is the principal (the initial amount invested), r indicates the annual interest rate, and t stands for the duration in years.

i = prt

i = 8700 * 0.03 * 7

i = 1827

Answer: B. $1827
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David has been tasked with tracking the number of bagels sold (y) at freddy's 24-hour bagel shop from 12: 00 am (x= 0) to 12: 00
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Let’s assume he sold 5 bagels, hence the calculation would be for 5 bagels sold.

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A researcher is studying a group of field mice. the distribution of the weight of field mice is approximately normal with mean 2
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A scientist needs 10 liters of a 20% acid solution for an experiment, but she has only a 5% solution and a 40% solution. To the
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An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, th
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Answer:

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9.9676 + 2.326*0.5904 =11.341

Step-by-step explanation:

Notation

\bar X is the sample mean

\mu indicates the population mean (the variable of interest)

s signifies the sample standard deviation

n denotes the sample size

Solution to the problem

The mean's confidence interval is derived from the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In this instance, the 9% confidence interval corresponds to:

8.8104 \leq \mu \leq 11.1248

We can determine the mean using the following:

\bar X = \frac{8.8104 +11.1248}{2}= 9.9676

Additionally, the margin of error can be calculated as:

ME= \frac{11.1248- 8.8104}{2}= 1.1572

The margin of error for this situation is expressed as:

ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE

Next, we find the standard error:

SE = \frac{ME}{t_{\alpha/2}}

The critical value for a 95% confidence interval using a normal standard distribution is roughly 1.96, and substituting gives us:

SE = \frac{1.1572}{1.96}= 0.5904

For the 98% confidence interval, the significance corresponds to \alpha=1-0.98= 0.02 and \alpha/2 = 0.01 with a critical value of 2.326, yielding a confidence interval of:

9.9676 - 2.326*0.5904 =8.594

9.9676 + 2.326*0.5904 =11.341

8 0
2 months ago
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