A researcher is studying a group of field mice. the distribution of the weight of field mice is approximately normal with mean 2

Jason can confirm the accuracy of his solution by substituting the calculated x value back into the original equation to check if it holds true. If the equality fails, it indicates that his calculated x is incorrect.

BD=7x-10
Solution: x=bd/7 + 10/7

BC=4x-29
Solution: x=Bc/4 + 29/4

CD=5x - 9
Solution: x= cd/5 + 9/5

A. Mean and standard deviation.

The sampling distribution’s mean closely matches the population mean. Since the population mean is 174.5, the sampling distribution’s mean equals this value.

The standard deviation of the sampling distribution is:

            σₓ̄ = σ / √n

Plugging in values:

            σₓ̄ = 6.9 / √25 = 1.38

b. Calculate z-scores for both values:
         
      z = (value - mean) / standard deviation

For 172.5:
     z = (172.5 - 174.5) / 1.38 = -1.49
Corresponding probability ≈ 0.068

For 175.8:
   z = (175.8 - 174.5) / 1.38 = 0.94
Corresponding probability ≈ 0.83

The difference between these probabilities is 0.762.

Approximately 0.762 × 200 = 152 sample means lie between 172.5 and 175.8.

c. Z-score for 172 cm:

    z = (172 - 174.5) / 1.38 = -1.81
Probability ≈ 0.03

Hence, samples with means below 172 cm equal 0.03 × 200 = 6.

Answer:

The segments of the positive graph are located at the coordinates (-5,-4) and (2,5).

In contrast, the negative segment is identified as (-4,2).

Step-by-step explanation:

The positive graph is above the x-axis, while the negative portion lies beneath the y-axis.

Within the interval (-1,5),

The graph appears below the x-axis between (-1,2)

And above it between (2,5).

At this juncture, Lonzell’s assertion is inaccurate.

Within the interval (-5,-1),

The graph again resides below the x-axis in the range (-4,-1)

And above it between (-5,4).

At this point, Lonzell's assessment remains incorrect.

Thus,

The segments of the positive graph are at the coordinates (-5,-4) and (2,5).

Meanwhile, the negative segment is identified at (-4,2).

Answer:

60

Step-by-step explanation:

The function provided is:

The average rate of change of h(t) as time goes from t=a to t=b is expressed as:

This function can be reformulated as:

The rocket's peak height is 231, which occurs at t=3.75 seconds.

The initial launch happens at: t=0

and

The average rate of change from launch to max height is