Response:
As the runner accelerates to peak speed, he then decelerates to reach the finish line.
Step-by-step clarification:
Maintaining a steady pace of 11 mph throughout his 32-minute run, the distance covered would be:
This indicates that to complete the 6.2-mile race, the runner needs to exceed 11 mph. Assuming he starts from a standstill, he accelerates to over 11 mph. Since he comes to a stop at the finish line, the runner must slow down from his higher speed (which is above 11 mph), passing through 11 mph before ultimately halting.
It is understood that
A direct variation exists between two variables, x and y, if it can be represented as
In this particular scenario
Define
x--------> the count of cans
y-------> the expense of a soup
therefore
when
substituting
the resulting equation is
by utilizing a graphing tool
refer to the figure attached
the solution is depicted in the attached figure
∠ROT=160°
∠SOT=100°
Now we calculate ∠SOR as follows: ∠SOR = ∠ROT - ∠SOT
∠SOR = 160° - 100°
∠SOR = 60°
It is stated that the angles ROQ, QOS, and POT all have the same measure.
Thus, ∠SOQ + ∠QOR = 60°
Since ∠SOQ equals ∠QOR, we can express this as:
2∠SOQ = 60°
From which we find ∠SOQ = 60° ÷ 2
∠SOQ = 30°
Also, ∠POT = ∠SOQ = ∠ROQ = 30°
