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ASHA 777
2 months ago
15

the average sneeze can travel 3/100 mile in 3 seconds. at this rate how far can it travel in 1 minute​

Mathematics
2 answers:
Leona [12.6K]2 months ago
6 0
In 1 minute, it would travel 60/100 miles since if it covers 3/100 mile in 3 seconds, it implies that traveling 1/100 mile takes one second and hence a minute (60 seconds) equates to 60/100 of a mile.
Leona [12.6K]2 months ago
4 0
The answer is 0.6 mile. Step-by-step explanation: Given the distance covered in 3 seconds is \frac{3}{100} miles, we need to ascertain the distance it can cover in a minute. Since it can travel \frac{3}{100} miles in 3 seconds, in 1 second it covers \frac{3}{100\times3} =\frac{1}{100} miles. Consequently, over 60 seconds (1 minute), the distance traveled is calculated as mile. Thus, it will reach 0.6 mile in one minute.
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Evaluate 0.1m+8-12n0.1m+8−12n0, point, 1, m, plus, 8, minus, 12, n when m=30m=30m, equals, 30 and n=\dfrac14n= 4 1 ​ n, equals,
PIT_PIT [12445]

Answer:

8

Step-by-step explanation:

The task is to evaluate:

0.1m + 8 - 12n

When m=30, n=\frac{1}{4}

By substituting these values into the expression, we have:

0.1m+8-12n=0.1(30)+8-12(\frac{1}{4})\\=3+8-\frac{12}{4}\\=3+8-3\\=8

8 0
1 month ago
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A coordinate grid with 2 lines. The first line is labeled y equals negative StartFraction 7 over 4 EndFraction x plus StartFract
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Question 1: (2.2, -1.4). Question 2: (1.33, 1). Providing a detailed analysis, the equations for the given lines are specified as (1) passing through points (0, 2.5) and (2.2, 1.4), and (2) through (0, -3) and (2.2, -1.4). We are tasked with locating a common solution or intersection of these equations. This leads to finding x = 2.2, and consequently y = -1.4. Therefore, the solution set is (2.2, -1.4). For question 2, the equations yield a solution of (1.33, 1).
5 0
2 months ago
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On her birthday, Sonia distributed chocolates in an orphanage. She gave 5 chocolates to each child and 20 chocolates to adults.
Svet_ta [12734]

Answer with explanation:

Total number of children = x

Total chocolates shared = y

In total, the chocolates distributed to the children equals 5 times the number of children, or 5 x.

Chocolates received by adults equal 20.

Let the number of adults be z.

Expressing this situation as an equation:

y = 5 x + 20 z

z=\frac{y-5 x}{20}

⇒Number of adults = z

       =\frac{y-5 x}{20}

3 0
2 months ago
The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [12365]
\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
2 months ago
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