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Marysya12
2 months ago
11

A storage closet holds twelve boxes stacked upon each other, with each box being 10 inches high. How many feet are there between

the top of the third box and the bottom of the tenth box?
Mathematics
2 answers:
babunello [11.8K]2 months ago
6 0

Answer: 5

Explanation step-by-step: There are six boxes stacked between the top of the third box and the bottom of the tenth box.

Since each box measures 10 inches in height, the combined height of these six boxes is 60 inches.

Given that 12 inches equals 1 foot,

60 inches corresponds to 5 feet.

How to find the answer:

Let "y" represent the unknown length in feet.

12 inches = 1 foot

60 inches = y

Using cross multiplication:

> 12 × y = 60 × 1

> 12y = 60

Divide both sides by 12 to solve for "y":

> 12y ÷ 12 = 60 ÷ 12

After simplification, we get:

> y = 5

lawyer [12.5K]2 months ago
4 0

Answer:

The distance between the top of the third box and the bottom of the tenth box is 5 feet.

Step-by-step explanation:

First, determine the number of boxes between the specified points, then convert the total height from inches into feet.

The phrase "top of the third box" refers to just above the third box, so measurement starts at the fourth box. Similarly, "bottom of the tenth box" means up to the bottom of the tenth box, which is just below the ninth box. Therefore, the number of boxes between these points is 6.

Each box has a height of 10 inches, so total height equals 6 × 10 inches = 60 inches.

To convert 60 inches into feet, recall 1 foot = 12 inches, then apply a proportion:

60in\frac{1ft}{12in}=5ft

Thus, 60 inches equals 5 feet.

Consequently, the distance from the top of the third box to the bottom of the tenth box is 5 feet.

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